How Do You Simplify an Equation Involving Natural Logarithms?

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Homework Help Overview

The discussion revolves around simplifying an equation involving natural logarithms, specifically the equation lny = lnx + BlnK + (1 - B)lnL. The original poster seeks assistance in transforming this equation to eliminate the natural logarithms using properties of logarithms and exponentials.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of logarithmic properties to combine terms and simplify the equation. There are questions about the necessity of showing work and the implications of accepting incorrect answers.

Discussion Status

The discussion includes various perspectives on the original poster's request, with some participants offering insights into logarithmic identities while others express concerns about the lack of demonstrated effort. There is no clear consensus on the best approach, but some guidance on using properties of logarithms has been provided.

Contextual Notes

Participants note the original poster's reluctance to show their work and the implications of that choice in the context of homework help. There is an underlying tension regarding the expectations of effort in problem-solving discussions.

Curious6
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Hey, I really would appreciate some help with this one as I'm stuck on my coursework. It'll probably be easy for most of you but I forgot how to do this operation with logarithms. See this equation:

lny = lnx + BlnK + (1 - B)lnL.

How can I change that to one that removes the natural logarithms by means of using x = e^lnx? Thanks in advance!
 
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Thank you very much!
 
This is really hilarious! You ask for someone to do your homework for you, showing absolutely no work of your own, then someone gives you a WRONG answer and you accept it without a thought!


ea+b is NOT equal to ea+ eb!

But A ln x= ln xA and ln x+ ln y= ln xy. Use those to write the left hand side as a single logarithm.
 
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HallsofIvy, please react proportionately to the situation. It was just a simple question and no big deal; the equation was just one out of a couple of alternatives I could solve to proceed with my coursework. I felt it was an insignifcant question so I didn't really believe it necessary to show all my workings. Nevertheless, thank you for your input.
 
Curious, that is pretty proportional. The situation is extremely ironic, and from now on if someone posts a question without showing work, I'm going to offer three possible solution routes, only one of which is correct. Absolutely brilliant.
 
Office_Shredder said:
The situation is extremely ironic.

Talking about sound judgement and proportionality...
 
Should I have said nothing and let you think you had a correct answer?
I don't dislike you that much!

I pointed out that you were making a mistake and explained how to get the correct answer. And you criticize me?
 

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