Integration by parts involving exponentials and logarithms

xllx
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Homework Statement



Using integration by parts, integrate:
(1/x^2)(lnx) dx with the limits e and 1


Homework Equations



[uv]to the limits a b - the integral of (v)(du/dx) dx

(sorry, don't know how to write out equations properly on a computer)

The Attempt at a Solution



I've got u=x^-2 so du/dx= -2x^-3
dv/dx=lnx so v= x(lnx-1)

So putting this into the equation above:
[x^-2.x(lnx-1)] - the integral of (-2x^-3.x(lnx-1))

Is this right so far?
If so how do I integrate the last part? Do I do it sepeartley or by parts again?

Many Thanks, any help at all would be greatly appreciated.
 
on Phys.org
Hi xllx! :smile:

(have an integral: ∫ and try using the X2 tag just above the Reply box :wink:)
xllx said:
Using integration by parts, integrate:
(1/x^2)(lnx) dx with the limits e and 1

I've got u=x^-2 so du/dx= -2x^-3
dv/dx=lnx so v= x(lnx-1)

So putting this into the equation above:
[x^-2.x(lnx-1)] - the integral of (-2x^-3.x(lnx-1))

eugh!

go the other way …

integrate x-2 ! :smile:
 
Thankyou. Redid it and came out with a reasonal answer.
 

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