How do you solve a differential equation using undetermined coefficients?

s7b
Messages
26
Reaction score
0
How do I go about solving a DE using the method of undetermined coeficients in a question like for example;

y''-4y'+4y=2e^2x

I tried assuming the yp to be Ae^2x but when I plugged it into the DE I ended up with 0=2e^2x


??
 
Physics news on Phys.org
Since '2' double root of your aux. eq'n.

the yp should be Ax^2e^2x
 
Once you substitute back into the original DE
Do you get:

8Ax^2e^2x + 2Ae^2x = 2e^2x
 
Thread 'Direction Fields and Isoclines'
I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...
Back
Top