How Do You Solve a Physics Problem Involving Forces and Motion?

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To solve the physics problem involving a 14kg lawn mower pushed with an 88N force at a 45-degree angle, it's essential to draw a free-body diagram to identify all acting forces. The horizontal component of the push can be calculated as 88N multiplied by the cosine of 45 degrees, while the vertical component uses the sine function. The normal force exerted by the ground must account for the mower's weight and the vertical component of the push. Additionally, to determine the force needed to accelerate the mower from rest to 1.5m/s in 2.5 seconds, the same friction force should be considered. Understanding these components is crucial for accurately solving the problem.
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Cant figure out how to do this problem??

A person pushes a 14kg lawn mover at constant sped with a force of 88N directed along the handle, which is at an angle of 45 degress to the horizontal. (a) draw the Free-body diagram showing all forces acting on the mower. (b) Calculate the horizontal friction force on the mower, then (c) the normal force exerted vertically upward on the mower by the ground. (d) What force must the person exert on the lawn mower accelerate it from rest to 1.5m/s in 2.5 seconds, assuming the same friction force?

This is a problem on my practice PCAT test for Pharmacy school. And its been a while since I have had physics so any help would be appreciated.

Thanks
 
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Well, what have you done? Have you drawn a free body diagram at least? Which parts of the question have you attempted?
 
Because the angle of the handle is 45 degrees, the force along the handle of 88N can be broken up into a horizonal force or square root of 2x88; and a vertical downward force of the same amount. I.e. 1.414 x 88 = 124.4 N.

Nelson
 
Nelson,

er, that's close but sin and cos 45 are actually= sqrt(2)/2=1/sqrt(2)=.707

On the other post, I mentioned what the Normal force is, so can you calculate it? Hint: weight plus vertical component of push but directed upwards. So what is weight?
 
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