How Do You Solve This Complex Quantum Mechanics Integral?

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Homework Statement



This is part of a much larger problem, however currently I am stuck at the following integral:

[tex] <br /> \int_{-\infty}^{\infty}exp\left(k^2\left((\Delta x)^2-\frac{i \hbar t}{2m}\right ) + k(ix-2(\Delta x)^2 \bar{k}_x)\right)dk[/tex]

Where obviously everything should be taken as a constant except the plane old k's.

Homework Equations



see (1) and (3)

The Attempt at a Solution



i tried to complete the square, followed by u/du substitution which yielded one of the messiest equations I've ever seen. There is an integral I found in a table that looks promising:

[tex]\int exp(-ax^2+bx+c)dx=\sqrt{\frac{\pi}{a}} exp\left(\frac{b^2}{4a}+c\right)[/tex]

However this does not include the imaginary unit therefore I do not believe it is much use to me.

Cookies for anyone who can get me started in the right direction.

Thanks yall!

IHateMayonnaise
 
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Your formula with a, b, & c is valid for complex a, b, & c as long as the real part of a is positive.

I think the [itex]k^2(\Delta x)^2[/itex] term in the exponent has the wrong sign.
 
Avodyne said:
Your formula with a, b, & c is valid for complex a, b, & c as long as the real part of a is positive.

I think the [itex]k^2(\Delta x)^2[/itex] term in the exponent has the wrong sign.

Why is the formula valid only if the real part of a is positive? (Also, this is assuming that it is a definite integral from [itex]-\infty[/itex] to [itex]\infty[/itex]?)

Good call on the [itex]k^2(\Delta x)^2[/itex] having the wrong sign! Thanks so much :)

Edit: Also I made a mistake in that integral from the table; I originally put:

[tex]\int exp(-ax^2+bx+c)dx=\sqrt{\frac{\pi}{a}} exp\left(\frac{b^2}{4ac}+c\right)[/tex]

but I meant:

[tex]\int exp(-ax^2+bx+c)dx=\sqrt{\frac{\pi}{a}} exp\left(\frac{b^2}{4a}+c\right)[/tex]
 
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