How do you work out the wavelegth (Franck-Hertz experiment)?

AI Thread Summary
In the Franck-Hertz experiment with potassium vapor, a significant drop in current occurs at 1.62V, indicating energy absorption. The energy change, delta E, is calculated as 1.62 eV, leading to the wavelength calculation using the formula lambda = hc/E. The correct wavelength for the spectral line is determined to be 767 nm, derived from the equation 1.24/eV. It is important to verify the constants used in calculations, such as Planck's constant and the speed of light, to ensure accuracy. Understanding these calculations is crucial for interpreting the emission spectrum of potassium.
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Homework Statement


In a Franck-Hertz experiment carried out with potassium vapour, it is found that the current falls off rapidly at an applied voltage of 1.62V. Calculate the wavelength of the expected spectral line in the emission spectrum of potassium when this voltage is reached.

Homework Equations


E = hf = hc/lambda

The Attempt at a Solution


delta E = 1.62 eV
lambda = hc/1.62 = 3.08x10^-25

According to a powerpoint, it should be 1.24/eV = 1.24/1.62 = 767nm (which is right). Where does 1.24 come from?
 
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