How Does a Ball's Velocity and Acceleration Change on a Circular Path?

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Homework Help Overview

The discussion revolves around a problem involving a ball moving in a circular path at a constant speed of 3.0 m/s, changing direction by 40.0 degrees over 1.75 seconds. Participants are exploring the concepts of velocity, acceleration, and the relationship between angular and translational speed in the context of circular motion.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the nature of velocity as a vector and the implications of changing direction on acceleration. There are attempts to relate angular speed to translational speed and to derive the radius of the circular path. Questions arise about the meaning of "change in velocity" and how it relates to acceleration.

Discussion Status

The discussion is active with various interpretations being explored. Some participants have made attempts at calculations and are seeking clarification on specific terms and concepts. Guidance has been offered regarding the relationship between angular and translational speeds, and the definition of change in velocity.

Contextual Notes

Participants note the absence of information regarding the radius of the circular path, which is a key component in solving the problem. There is also mention of potential confusion regarding the terminology used in the problem statement.

x86
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Homework Statement


A ball moving in the circular path with a constant speed of 3.0 m/s changes direction by 40.0 degrees in 1.75 seconds. What is the change in velocity? What is the acceleration during the time?


Homework Equations


Fc = m * ac
ac = v^2/r


The Attempt at a Solution


No clue to be honest, the velocity shouldn't change, because of the acceleration. And we don't know the radius, so I'm not sure how to solve this at all
 
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x86 said:
No clue to be honest, the velocity shouldn't change, because of the acceleration. And we don't know the radius, so I'm not sure how to solve this at all
Remember that velocity is a vector, with both a magnitude and a direction. If the direction changes, then there is acceleration.
 
tms said:
Remember that velocity is a vector, with both a magnitude and a direction. If the direction changes, then there is acceleration.

Right, the only thing i can see is 40 degrees / 1.75 seconds.

Okay, so the acceleration has to be 3 m/s^2 every time it changes direction... So if the direction changes everyone 1 second for the velocity to be 3 m/s the acceleration would have to be 3 m/s^2. I'm getting closer, I think

WAIT! I think I did it.

Period.

T = (360 degrees) / ((40 degrees) / (1.75 s)) = 15.75 s

D = vt

2pir = v * 15.75 s

r = 3.0 m/s * 15.75 s / (2 pi) = 7.52007106 meters

ac = v^2 / r = 9.0 m^2/s^2 / 7.52 m =1.19680851 m / s^2 = 1.2 m/s^2

Now, to figure out velocity

1.2 m/s^2 * t = v

The final velocity = 1.2 m/s^2 * 1.75 s = 2 m/s

But it wants the change in velocity. I'm not sure what this means? What is change in velocity?
 
Last edited:
x86 said:
Right, the only thing i can see is 40 degrees / 1.75 seconds.
That is the angular speed. You also have the translational speed. Find a relation between those two quantities (that will give you [itex]r[/itex]).
Okay, so the acceleration has to be 3 m/s^2 every time it changes direction...
An object in uniform circular motion is always changing direction.
 
tms said:
That is the angular speed. You also have the translational speed. Find a relation between those two quantities (that will give you [itex]r[/itex]).

An object in uniform circular motion is always changing direction.

Yes, I made an attempt at the solution and I think its right. But, what do they mean by change in velocity? I have no idea what this could mean.

The final velocity is 2.0 m/s. But the change would be something I'm not sure of. They could mean delta V, but then again that would give me an answer of 1.0 m/s, and the book says the answer is 2.0 m/s. But the book confirms the acceleration is correct.

EDIT: nevermind. i get it now.

The change in direction accounts for the change in velocity. Therefore, 1.2 m/s^2 * 1.75 seconds (time its changing) = 2.1 m/s which is the answer.

Thank you for those tips by the way, they helped me solve the problem. I totally forgot about period and such
 
Last edited:
x86 said:
But, what do they mean by change in velocity?
Change in velocity is just the definition of acceleration. It does sound a bit like a trick question, asking for the same thing twice using different words.
Thank you for those tips by the way, they helped me solve the problem. I totally forgot about period and such
You're welcome.
 

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