MHB How Does a Small Offset in Metal Pieces Increase with Distance?

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A small offset in metal pieces can significantly increase with distance from the center. In this case, an initial offset of 0.6mm becomes 3.3mm when the distance increases from 76mm to 420mm. This calculation involves determining the scaling factor by dividing the longer distance by the shorter one, resulting in approximately 5.5. Multiplying the original offset by this factor shows how the error amplifies. Understanding this relationship is crucial for ensuring proper alignment in mechanical assemblies.
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Hello all, sorry for the basic question but I suck at math and it's been many years since I had a course.

Anyway I've got two pieces of metal that bolt together and ideally are square and centered. However the pieces are not exactly square when bolted. The smaller piece is off by about .6mm. I need to know how big that mistake becomes further away from the center.

To put it into terms of a triangle where the first of two mounting holes is a point that is fixed: Side A is 76mm, side B (the second hole offset) is .6mm. So what would side B become if side A is now 420mm?

That's the first part of my question. Thanks!
 
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Divide 420 by 76

$$\frac{420}{76}\approx 5.5$$

So, multiply 0.6 with 5.5

$$0.6\cdot 5.5= 3.3$$

So side b is 3.3 mm
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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