How Does a Uniform Spherical Charge Influence a Linear Charge Along the Z-Axis?

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SUMMARY

The discussion focuses on calculating the force exerted on a linear charge along the Z-axis due to a uniform spherical charge distribution centered at the origin. The total charge of the line charge is represented as λL, while the spherical charge is quantified as (4/3)πa³ρ, where ρ is the charge density. The force on a differential segment of the line charge is derived using Coulomb's law, resulting in the expression (λL a³ρ)/(3εz²). However, an error is identified in the integration process, leading to an incorrect factor of L² instead of L in the final result.

PREREQUISITES
  • Understanding of linear charge density (λ) and its implications in electrostatics.
  • Familiarity with Coulomb's law and the concept of force between point charges.
  • Knowledge of spherical charge distributions and their properties.
  • Basic calculus skills for performing integration over continuous charge distributions.
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  • Study the derivation of electric fields due to continuous charge distributions.
  • Learn about the method of integration in electrostatics, particularly for line and surface charges.
  • Explore the concept of electric potential and its relation to electric fields.
  • Investigate the implications of charge distribution on force calculations in electrostatics.
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Students and professionals in physics, particularly those specializing in electromagnetism, as well as engineers working with electrostatic applications and charge distribution analysis.

schattenjaeger
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A line charge of length L with lamba=const.(linear charge density) lies along the positive Z axis with its ends located at z=z0 and z0+L. Find the total force on the line charge due to a uniform spherical charge distribution with center at origin and radius a<z0

Sooo here's what I DID

I knew the total charge contained on the line charge was lamba*L, and the total charge contained in the sphere was 4/3 pi a^3 * rho where rho was its charge density, and it could be treated like a point particle with that total charge since the line charge didn't go inside it.

So my vector going from the origin to my field point was r=zk(k unit vector in z direction)and r'=0 since the source point was on the origin,so R^2=z^2

so the Force on a point on the line charge I took to be q*q'/r^2 in the z direction which was, after simplifying, (lamba*L*a^3*rho)/(3ez^2) where e is permitivitty of free space or whatever. so integrating over the whole line charge, ie F=S(allthat)*dz from z0 to z0+L, well, ALMOST gave me the right answer, I got an L^2 in the final answer when there should be just a single L

so I think earlier when I was finding the force at a point on the line charge, I had to JUST use lambda and not the whole line charge lamda*L?
 
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I think you have got the problem, and cahrge on each elemnent of the stick is Lam.dr.
 

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