How Does Accelerating on an Incline Affect G-Force?

AI Thread Summary
Accelerating on an incline affects the g-force experienced in a vehicle. When accelerating at 1 m/s² on a 45-degree incline, the g-force on the back can be calculated by resolving the forces acting on the body. This involves using a free body diagram to analyze the weight component parallel to the incline and adding the force from the acceleration. The total force experienced is the sum of the gravitational force component and the acceleration force. Understanding these calculations is crucial for accurately determining the g-force in such scenarios.
IMK
Messages
61
Reaction score
0
Hello,
I am in a car and accelerating on the horizontal at a rate of say 1mss I wound be subjected to 0.1g acceleration on my back, correct?

However if I accelerate in the same car at the same 1mss up and incline of 45 degrees what would be the g force on my back please? And how do I calculate it , is it the sine of the angle of incline of gravity + my the 1mss driving acceleration.

Many thanks IMK
 
Physics news on Phys.org
IMK said:
I am in a car and accelerating on the horizontal at a rate of say 1mss I wound be subjected to 0.1g acceleration on my back, correct?
Assuming g = 10 m.s-2, yes.
IMK said:
However if I accelerate in the same car at the same 1mss up and incline of 45 degrees what would be the g force on my back please? And how do I calculate it , is it the sine of the angle of incline of gravity + my the 1mss driving acceleration.
You would draw yourself a free body diagram and examine the forces acting, resolving them parallel to the slope. And yes, you would find that the force exerted at your back would be the sum of your [combined] weight, resolved parallel to the incline and the force due to the 0.1g acceleration. Note it is always best in this case to work with forces first and then resolve into an acceleration.
 
Last edited:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top