How Does Ampere's Law Calculate Current in a Uniform Magnetic Field?

AI Thread Summary
The discussion focuses on using Ampere's Law to calculate the conventional current enclosed by a circular path in a uniform magnetic field. The magnetic field strength is given as 1.4e-06 T, and the radius of the path is 0.03 m. One participant consistently arrives at a current value of 3.19e4 A, which is questioned due to a significant discrepancy in magnitude. It is clarified that the vacuum permeability constant (μ0) should be used instead of the vacuum permittivity constant (ε0) in the calculations. The correct application of Ampere's Law is essential for accurate results in this scenario.
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Homework Statement


Along a circular path the magnetic field is measured and is found to be uniform in magnitude and always tangent to the circular path.
If the radius of the path is 0.03 m and B along the path is 1.4e-06 T, use Ampere's law to calculate the magnitude of the conventional current enclosed by the path.

Homework Equations


ampere's law -- integral(B*dl) = mu I

The Attempt at a Solution


i keep getting 3.19e4 A
 
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Hello ineedhelp5454,

Welcome to Physics Forums!
ineedhelp5454 said:
i keep getting 3.19e4 A
My answer is different by 5 or so orders of magnitude.

Show us your steps and maybe we can help figure out what's going on.
 
1.5e-6 * 2 * pi * .03 = 2.87e-7 (left half of ampere's equation)
2.87e-7 = 8.85e-12(mu) * I (right half)
I = 3.19e4
 
ineedhelp5454 said:
1.5e-6 * 2 * pi * .03 = 2.87e-7 (left half of ampere's equation)
Is the magnitude of B 1.5 x 10-6 or 1.4 x 10-6 T?
2.87e-7 = 8.85e-12(mu) * I (right half)
I = 3.19e4
You're using the vacuum permittivity constant ε0 = 8.854 x 10-12 F/m, but you need to use the vacuum permeability constant μ0= 4π x 10-7 H/m.

They're not the same thing, but they are related. The speed of light in a vacuum c = 1/\sqrt{\epsilon_0\mu_0}
 
thanks!
 
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