How Does an Electric Field Affect Electron Motion?

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SUMMARY

The discussion focuses on the motion of an electron in an electric field between charged parallel plates, specifically analyzing its acceleration and velocity. The electric field strength is given as E = 140 N/C, leading to an acceleration calculated using the formula a = (e/m) E, resulting in -2.45E13 m/s². The velocity of the electron when its x-coordinate changes by 3.6 cm is determined using kinematic equations, specifically V = sqrt(v0^2 + 2aD), where v0 is the initial velocity and D is the displacement.

PREREQUISITES
  • Understanding of electric fields and forces on charged particles
  • Familiarity with kinematic equations in physics
  • Knowledge of the charge and mass of an electron
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation of the equation a = (e/m) E for electron acceleration
  • Explore kinematic equations in two dimensions for particle motion
  • Learn about the effects of electric fields on charged particles in different contexts
  • Investigate the implications of electron motion in various electric field configurations
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism and particle motion, as well as educators seeking to explain the principles of electric fields and kinematics.

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[SOLVED] Electric Field Problem

Homework Statement



At some instant the velocity components of an electron moving between two charged parallel plates are Vx = 1.5E5 m/s and vy = 1.8E3 m/s. Suppose that the electric field between the plates is given by E = (140 N/C) j.

(a) What is the electron's acceleration in the field?

(b) What is the electron's velocity when its x coordinate has changed by 3.6 cm?

Homework Equations


I got the first answer doing ---- a = (e/m) E.

so the answer came out to be -2.45E13.

For b. you have to find the x portion for the velocity and the y portion of the veloctity

i found the x, it just stays the same and for the y:

Kinematics:

D = v0^2 - v^2 / (2a)

2aD = V0^2 - V^2

V = sqrt(v0^2 + 2aD)

The Attempt at a Solution


V = sqrt(v0^2 + 2aD)


Please help
 
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Find the time 't' for the x to change by 3.6 cm, which is easy since vx is constant.

For motion in y dircn, initial speed v_yi is given, the accn in y dircn you know, and so apply v_yf = v_yi + at.
 
thanx a lot for helping me out

it worked!
 

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