How Does an Electron Move in a Magnetic Field Within a Cloud Chamber?

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DiamondGeezer
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An electron enters a cloud chamber which has a magnetic field B but the path of the electron is not perpendicular to the magnetic field. I understand that the electron path will describe a spiral.

Does the v in the equation F = q(v x B) refer to the component of the electron's velocity which is perpendicular to the B field? Can I assume that an electron's velocity parallel to the B field remains constant and is unaffected by the B field?
 
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The [itex]\vec v[/itex] in that equation is the vector velocity of the electron, including all three (x, y, z) components in general. However, you're correct that the component of [itex]\vec v[/itex] parallel to [itex]\vec B[/itex] does not contribute to [itex]\vec F[/itex]. So if, for example, [itex]\vec B[/itex] is in the z-direction (i.e. [itex]B_x = B_y = 0[/itex]), then it doesn't matter what [itex]v_z[/itex] is, as far as [itex]\vec F[/itex] is concerned:

[tex]F_x = q (v_y B_z - v_z B_y)[/tex]

[tex]F_y = q (v_z B_x - v_x B_z)[/tex]

[tex]F_z = q (v_x B_y - v_y B_x)[/tex]
 
Thank you. That completely answers my question
 
clem said:
But it is a helix, not a spiral.

Correct.