How Does Archimedes' Estimation of Pi Hold for n=4, 8, 16, 32, ...?

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Discussion Overview

The discussion revolves around the relationship involving Archimedes' estimation of pi as it pertains to polygons with increasing numbers of edges (n = 4, 8, 16, 32, ...). Participants explore the algebraic and geometric implications of a specific equation related to the areas of these polygons.

Discussion Character

  • Exploratory
  • Mathematical reasoning

Main Points Raised

  • One participant presents a relationship involving the areas of polygons with n edges and seeks assistance in proving it.
  • Another participant questions the simplification of the equation, particularly regarding the square root and squaring process, suggesting a geometric interpretation of the areas involved.
  • A participant claims to have solved the problem but does not provide details immediately, indicating a desire to share the solution later.
  • There is a suggestion that sharing the solution would benefit future visitors to the thread.

Areas of Agreement / Disagreement

Participants express a mix of uncertainty and progress, with one claiming to have solved the problem while others await further clarification and a solution to be posted. No consensus is reached on the proof itself.

Contextual Notes

The discussion includes unresolved aspects of the algebraic manipulation and geometric interpretations of the areas, which may depend on specific assumptions or definitions not fully articulated in the thread.

nacho-man
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It has been eons since I've done any trigonometry, but I just can't prove how this following relationship holds for $n = 4, 8, 16, 32, \dots$

The relation is:
$$
2 \biggl( \! \frac{A_{2n}}{n} \! \biggr)^2 = \, 1 - \Biggl( \sqrt{1 - \frac{2A_n^{\phantom{X}}}{n}} \, \Biggr)^{\!2}
$$

I've subbed in points, and it definitely holds.

Using this image as reference, a polygon with $n$ edges and $A_n$ the entire area, we can estimate (albeit very slowly) a unit circle's area.View attachment 4126Any help would be appreciated.
 

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In your equation the right-hand-side takes a square root and then immediately squares the result, what does that amount to? Once you've simplified your equation using that fact, think about what $A_n / n$ and $A_{2n} / n$ represent geometrically, and you can then perhaps reduce the algebra problem to a geometric statement about triangles.
 
Bacterius said:
In your equation the right-hand-side takes a square root and then immediately squares the result, what does that amount to? Once you've simplified your equation using that fact, think about what $A_n / n$ and $A_{2n} / n$ represent geometrically, and you can then perhaps reduce the algebra problem to a geometric statement about triangles.
I have solved this problem now.

Thanks :)
 
nacho said:
I have solved this problem now.

Thanks :)

Great! It's good etiquette to post your solution so that future visitors who come across this thread can also benefit from it :)
 
Bacterius said:
Great! It's good etiquette to post your solution so that future visitors who come across this thread can also benefit from it :)

Yes! definitely.

I will post the solution some time next week, when my work has been assessed (don't want to post a solution with errors and mislead someone :( )
 

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