How Does Archimedes' Principle Determine Buoyant Force?

Thread starter skandol
Start date Jun 16, 2009

AI Thread Summary

Archimedes' Principle states that the buoyant force on an object submerged in fluid equals the weight of the fluid displaced by the object. To calculate the buoyant force on a rock with a volume of 5.96x10-6 m3, one must determine the weight of the equivalent volume of water. The density of water is approximately 1000 kg/m3, so the weight of the displaced water can be calculated using the formula: weight = density × volume × gravity. This results in a buoyant force equal to the weight of the displaced water. Understanding these calculations is essential for solving buoyancy-related problems.

Jun 16, 2009

skandol

Achimedes' Prinicple! HELP

Homework Statement

A rock has a volume of 5.96x10-6 m3. When it is completely submerged in a beaker of water, the water exerts a buoyant force on the rock equal to ___ Newtons.

Homework Equations

Kind of confused...

d=m/v

B= densityofwater (voulme)

is that correct?

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Jun 16, 2009

mgb_phys

Science Advisor

Homework Helper

The force is equal to the weight of water displaced
How much does 5.96x10-6 m3 of water weigh?

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