How Does Braking Affect the Temperature of Car Brakes?

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Braking a car converts its kinetic energy into heat, which raises the temperature of the brakes. For a 758 kg car moving at 25 m/s, the initial kinetic energy can be calculated using the formula 1/2 mv^2. The heat energy absorbed by the brakes, denoted as Q, is equal to this kinetic energy. The specific heat formula Q=mc(t1-t2) can then be used to find the increase in temperature of the brakes. Thus, the change in temperature can be determined by equating the kinetic energy to the heat absorbed by the iron brakes.
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A 758 kg car moving at 25 m/s brakes to a
stop. The brakes contain about 16 kg of iron
that absorb the energy.
What is increase in temperature of the
brakes? Assume the specific heat of iron is
450 J=kg ¢
± C. Answer in units of ±C.Q=mc(t1-t2)

Ok I have the mass of the brakes and the specific heat and I know you only have to solve for the change in temperature, so I all need is Q.
I know Q is measured in Joules and J=Newton x distance, but all I am given is the velocity of the car, nothing about time, distance, or Acceleration. So how do you figure the Q?
 
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Cortar said:
A 758 kg car moving at 25 m/s brakes to a
stop. The brakes contain about 16 kg of iron
that absorb the energy.
What is increase in temperature of the
brakes? Assume the specific heat of iron is
450 J=kg ¢
± C. Answer in units of ±C.


Q=mc(t1-t2)

Ok I have the mass of the brakes and the specific heat and I know you only have to solve for the change in temperature, so I all need is Q.
I know Q is measured in Joules and J=Newton x distance, but all I am given is the velocity of the car, nothing about time, distance, or Acceleration. So how do you figure the Q?

It comes to a stop so all the initial kinetic energy (1/2 mv^2) goes into heat. That's your Q
 
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