How does Changing Salt Bridge Solution affect observed voltages?

AI Thread Summary
Changing the salt bridge solution from potassium nitrate to zinc nitrate primarily affects the observed voltages in the half-cell containing Zn2+. The reduction potential of Zn2+ is +0.76 V, which can influence the electrochemical reactions depending on its position as anode or cathode. If Zn2+ is at the anode, the potential difference will increase, while it will decrease if placed at the cathode. Although the salt bridge does not alter electrode reactions, variations in solution can affect resistance, impacting overall cell performance. Understanding these dynamics is crucial for accurate predictions of cell potentials.
faradayslaw
Messages
48
Reaction score
0

Homework Statement


In a lab in which many half-cells are constructed, one of which contains Zn2+, the original salt bridge solution is Potassium nitrate. Suppose we needed to change this solution to Zinc nitrate. What would be the effect on the observed cell potentials?


Homework Equations


Reduction Potential of Zn2+ = +0.76 V
Ecell=Ecathode-Eanode

The Attempt at a Solution


So it seemed at first that the observed voltages would not be altered in all half cells except that with the Zn 2+ ions, since the Zn 2+ ions are not involved in the half-cell reactions, but on the other hand, the high reduction potential of Zn2+ may lead to Zn2+ reducing, rather than the actual metal cations in the anode.

Moreover, for the Zn2+ half cell, the potential difference would increase if the Zn2+ was the anode, and would decrease if Zn2+ was in the cathode.

Please let me know if this is the correct way to think about the problem

Thanks,
 
Physics news on Phys.org
Salt bridge doesn't change electrode reactions, however, different solution may have different resistance.
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top