How Does Coil Orientation Affect Mutual Inductance Calculation?

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Discussion Overview

The discussion revolves around calculating the mutual inductance between a rectangular coil and an infinite straight filament. Participants explore the mathematical expressions and coordinate transformations necessary for the calculation, particularly focusing on the orientation of the coil and its effects on the mutual inductance in free space.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant outlines the problem and expresses confidence in solving it when the coil is parallel to the y-z plane, but becomes confused when considering the coil's orientation affecting the expression for r, which varies with x, y, and z.
  • Another participant suggests expressing the magnetic field B and the area element dA in Cartesian coordinates, indicating that the B field will have components in the i and j directions.
  • There is a discussion about the relationship between polar and Cartesian coordinates, with a participant questioning how to express r in terms of x and y.
  • One participant presents a modified expression for B and dS, changing the differential area from dydz to dydx, and seeks confirmation on this adjustment.
  • Another participant acknowledges the progress made and encourages further exploration of the integration process, while also noting the complexity of the closed-form results.
  • There is a mention of using Wolfram Alpha for calculations, with participants expressing appreciation for its utility in solving integrals.

Areas of Agreement / Disagreement

Participants generally agree on the approach to the problem and the use of mathematical tools, but there remains uncertainty regarding the correct expressions and integration methods. The discussion does not reach a consensus on the final solution or the best method for integration.

Contextual Notes

Participants express confusion about the transformations and coordinate systems involved, particularly regarding the expressions for r and dS. There are unresolved questions about the correctness of the changes made to the differential area element and the implications of the coil's orientation on the calculations.

niggchao
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Homework Statement


A rectangular coil is composed of 150 turns of a filamentary conductor. Find the mutual inductance in
free space between this coil and an infinite straight filament on the z axis if the four corners of the coil
are located at
2gud0eg.png


Homework Equations



B = (phi-hat) μoI/2πr
dS = (n-hat) dydz

2dgkvv5.png
[/B]

Φ = ∫B⋅dS

The Attempt at a Solution


I can easily solve this problem if the coil is parallel to the y-z plane and x = 1 since the r in the formula varies only on y thus, becomes sqrt(y2 + 1) then convert phi-hat to cartesian unit vectors and the area unit vector is just -(x-hat).

Now, in this problem, I have converted the area unit vector to its cartesian unit vector. I am confused on how I will write the expression for r since it now varies on x, y, and z?
 
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I would suggest the following:
Express the B field and the element of area dA in cartesian coordinates. Then form the integral φ = ∫B⋅dA and you know the rest I assume.
The element dA has a vector normal to the described area & will consist of an i and a k component as I think you can see. The B field will have an i and a j component.
i, j and k are unit vectors in the x, y and z directions. Vectors are in bold.

There may be a shortcut method but I don't see one at the moment.
 
Last edited:
niggchao said:
I am confused on how I will write the expression for r since it now varies on x, y, and z?
What relates polar (r, θ) to cartesian coordinates x and y? r is not a function of z.
 
Last edited:
79eb09cbb46123591264cf57618a757b.png
and http://www4f.wolframalpha.com/Calculate/MSP/MSP6082070f83052eaehe200002h13c1i6iciah25i?MSPStoreType=image/gif&s=40&w=93.&h=28. then
B = (-
8baf9dc7043aae61e37e171dc9f537e9.png
sinφ +
7b5fdad25716879ce0706bf95efd82c0.png
cosφ) μoI/2π*sqrt(x2+y2)
dS = (-[PLAIN]https://upload.wikimedia.org/math/8/7/5/875326710761d5ed42bdc6e30c4bf962.pngcos45 - [PLAIN]https://upload.wikimedia.org/math/8/b/a/8baf9dc7043aae61e37e171dc9f537e9.pngsin45) dydx I changed it from dydz to dydx because my variables in the integral are x and y. Is this okay?

Then integrate the dot product to get the flux.
What do you think?
 
Last edited by a moderator:
niggchao said:
79eb09cbb46123591264cf57618a757b.png
and http://www4f.wolframalpha.com/Calculate/MSP/MSP6082070f83052eaehe200002h13c1i6iciah25i?MSPStoreType=image/gif&s=40&w=93.&h=28. then
B = (-
8baf9dc7043aae61e37e171dc9f537e9.png
sinφ +
7b5fdad25716879ce0706bf95efd82c0.png
cosφ) μoI/2π*sqrt(x2+y2)
dS = (-[PLAIN]https://upload.wikimedia.org/math/8/7/5/875326710761d5ed42bdc6e30c4bf962.pngcos45 - [PLAIN]https://upload.wikimedia.org/math/8/b/a/8baf9dc7043aae61e37e171dc9f537e9.pngsin45) dydx I changed it from dydz to dydx because my variables in the integral are x and y. Is this okay?

Then integrate the dot product to get the flux.
What do you think?
I think you're off to a great start!

B = (-
8baf9dc7043aae61e37e171dc9f537e9.png
sinφ +
7b5fdad25716879ce0706bf95efd82c0.png
cosφ) μoI/2π*sqrt(x2+y2),
what are cosφ and sinφ in terms of x and y?

dS = (-[PLAIN]https://upload.wikimedia.org/math/8/7/5/875326710761d5ed42bdc6e30c4bf962.pngcos45 - [PLAIN]https://upload.wikimedia.org/math/8/b/a/8baf9dc7043aae61e37e171dc9f537e9.pngsin45) dydx is almost right. This is the tricky part. Your area element is dy times the differential distance along the sloping area. Call it dζ. So your differential area is dydζ.
Can you see that dζ2 = dx2 + dz2 ? But you can eliminate dz; what is it in terms of dx? Your differential area can then be (constant)*dxdy, multiplied by the normalized normal vector S. To check that you got the right constant, just integrate (constant)*∫∫dy dx over the limits given you. You know the area has to come out to 3√2.

The rest is as you say. Don't forget N = 150 and mutual inductance is a positive number.
 
Last edited by a moderator:
Not really sure if I understood the dS part but I'll try

wi57ro.png

cos45 = dx/dζ
dζ = dx/cos45
dS = (1/cos45) dxdy

dS = (-[PLAIN]https://upload.wikimedia.org/math/8/7/5/875326710761d5ed42bdc6e30c4bf962.pngcos45 - [PLAIN]https://upload.wikimedia.org/math/8/b/a/8baf9dc7043aae61e37e171dc9f537e9.pngsin45) (1/cos45) dxdy

I did integrate dS and got 3√2 but I'm afraid this might be a coincidence. What do you think?
 
Last edited by a moderator:
niggchao said:
dS = (-[PLAIN]https://upload.wikimedia.org/math/8/7/5/875326710761d5ed42bdc6e30c4bf962.pngcos45 - [PLAIN]https://upload.wikimedia.org/math/8/b/a/8baf9dc7043aae61e37e171dc9f537e9.pngsin45) (1/cos45) dxdy
which if you'll permit me = - k - i :smile:
I did integrate dS and got 3√2 but I'm afraid this might be a coincidence. What do you think?
I think it's no coincidence. I think you're banging at the door.
So now, proceed to do the integration? A word of warning: there are of course two ways to do the double integration over x and y. You will be appalled at how messy the closed-form results are either way. BUT - if you do what I did and let wolfram alpha do the definite integrals you happily get the same numerical answer either way, as of course you should. So if you get an answer we can compare notes.
 
Last edited by a moderator:
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Thank you sir! This wolfram alpha is amazing. I didn't know something like this exists. Thanks again!
 
niggchao said:
Thank you sir! This wolfram alpha is amazing. I didn't know something like this exists. Thanks again!
Yes, WA is a miracle. I hope you have access to the Pro version. As a retiree I can't afford the premiums but luckily I didn't need too much computing time for the integrals. Nice work.
 

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