How Does Conservation of Momentum Apply in a Frictionless Sled Problem?

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SUMMARY

The discussion focuses on applying the principle of conservation of momentum to a frictionless sled problem involving a 120 kg sledge and a 70 kg man. When the man walks 3 meters towards the shore, the system's center of mass remains stationary due to the absence of external forces. The equation 70(Rm) + 120(Rs) = 0 is used to relate the distances from the man and the sledge to the center of mass, allowing for the calculation of the man's final position relative to the shore.

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  • Understanding of conservation of momentum principles
  • Knowledge of center of mass calculations
  • Familiarity with basic physics equations
  • Concept of frictionless surfaces in physics
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  • Learn how to apply conservation laws in different physical scenarios
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PatsObi
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I'm stuck on this problem.

A sledge of mass 120 kg is at rest on a horizontal icy surface. A man of mass 70 kg stands at one end of the sledge so the initially the distance from the man to the shore is 20 m. The man now walks 3 m relative to the sledge, towards the shore. The he stops. Assuming the moves w/out friction, how far from the shore is the man when he stops.

THis is pretty much all i know:

70(Rm)+120(Rs)=0

where Rm and Rs are the distances from the man to the cm and the cm of the sledge to the cm respectfully.
 
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PatsObi said:
THis is pretty much all i know:

70(Rm)+120(Rs)=0

where Rm and Rs are the distances from the man to the cm and the cm of the sledge to the cm respectfully.

That is actually all you need, but with some understanding. Can you tell me what this eqn signifies? And how to find the CM of the system wrt the shore? After that, we can form the necessary eqns.

Also, the word you were looking for is "respectively", not respectfully.
 

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