How Does Friction Impact Tug of War Dynamics?

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In a tug of war on a sandy beach, Team A has six players averaging 65 kg, while Team B has five players averaging 84 kg. Team B exerts a pulling force of 3200 N to dislodge Team A and then maintains a force of 2900 N to keep Team A moving at constant velocity. The static friction coefficient for Team A is calculated as 0.22 based on the normal force and the applied force. The discussion highlights the importance of considering all players' weights in calculating friction dynamics. Understanding these forces is crucial for analyzing the physics of tug of war.
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Homework Statement



In a game of tug of warcontest on a firm, horizontal sandy beach, Team A consists of six players with an average mass of 65 kg and Team B consists of 5 players with an average mass of 84 kg. Team B pulling with a force of 3200 , dislodges Team A and then applies good physics principles and pulls on Team A with a force of 2900 , just enough to keep Team A mov ing a at constant velocity. What is Team A's?
a. static friction
b. kinetic friction

Homework Equations


uS = Fs/Fn
uK = Fk/Fn


The Attempt at a Solution


Fn = Fg = mg
65 kg x 9.8N/kg
637 N
uS = 637 N/2900N
0.22
 
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You haven't stated a question. What's the purpose of your post?

It might be of interest to note that you've disregarded five of the six players on team A.
 

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