How does gravitational potential energy work?

In summary: Advanced Cosmology" you want to go but there's a reasonable classical argument that says that every tiny piece of mass has always affected every other tiny piece of mass (back to the big bang, at least).Taking that into account, do you want to elaborate on your question?
  • #1
TheQuestionGuy14
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Gravitational energy is the potential energy a physical object with mass has in relation to another massive object due to gravity, so, does an object outside a gravitational field have no gravitational potential energy?
For example, the Earth is 4.5 billion years old, so it's gravity stretches 4.5 billion lightyears, meaning objects further than this aren't affected by Earth's gravity. Once Earth's gravity reaches them, do they gain potential energy? How does this work?
 
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  • #2
TheQuestionGuy14 said:
does an object outside a gravitational field have no gravitational potential energy?
There is no such thing as being outside a gravitational field. Gravity from every single atom (in principle) extends throughout the universe.

TheQuestionGuy14 said:
For example, the Earth is 4.5 billion years old, so it's gravity stretches 4.5 billion lightyears,
The mass that makes up Earth has existed since the Big Bang (as energy, and then as atoms) - albeit being distributed throughout larger volume of space. Every one of those atoms has been exerting its gravitational pull on everything else in the universe (in principle).

The large volume of dust and gas that is destined to become Earth has been acting upon that object's individual atoms even before the atoms coalesced into the object, so the gravitational potential has always been there.
 
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  • #3
TheQuestionGuy14 said:
For example, the Earth is 4.5 billion years old, so it's gravity stretches 4.5 billion lightyears,
The majority of the mass of the Earth was 'somewhere else' before it got together to form the Earth. There has been a tiny amount of mass change due to Energy changes but we can ignore that here.
I'm not sure how "Advanced Cosmology" you want to go but there's a reasonable classical argument that says that every tiny piece of mass has always affected every other tiny piece of mass (back to the big bang, at least).
Taking that into account, do you want to elaborate on your question?
(I see that I have more or less repeated what Dave has already written but the fact that we came up with similar answers should help to convince you! :smile: )
 
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  • #4
DaveC426913 said:
There is no such thing as being outside a gravitational field. Gravity from every single atom (in principle) extends throughout the universe.The mass that makes up Earth has existed since the Big Bang (as energy, and then as atoms) - albeit being distributed throughout larger volume of space. Every one of those atoms has been exerting its gravitational pull on everything else in the universe (in principle).

The large volume of dust and gas that is destined to become Earth has been acting upon that object's individual atoms even before the atoms coalesced into the object, so the gravitational potential has always been there.

Ok, thanks, that makes sense.
 
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  • #5
sophiecentaur said:
The majority of the mass of the Earth was 'somewhere else' before it got together to form the Earth. There has been a tiny amount of mass change due to Energy changes but we can ignore that here.
I'm not sure how "Advanced Cosmology" you want to go but there's a reasonable classical argument that says that every tiny piece of mass has always affected every other tiny piece of mass (back to the big bang, at least).
Taking that into account, do you want to elaborate on your question?
(I see that I have more or less repeated what Dave has already written but the fact that we came up with similar answers should help to convince you! :smile: )

Thanks, I understand. I assume the same applies to other fields like the electric field aswell?
 
  • #6
Hmm. Not sure about that because there are both positive and negative charges (of course) in nearly all matter so the effect at a distance of a particular charge can actually be zero due to other charges. Gravity is a bit special.
 
  • #7
Well, the net effect of gravity can be zeroed out as well, say, by having mass equally distributed about the target mass.
 
  • #8
DaveC426913 said:
Well, the net effect of gravity can be zeroed out as well, say, by having mass equally distributed about the target mass.
But that doesn't zero the potential, just the force.
 
  • #9
Ibix said:
But that doesn't zero the potential, just the force.
Yes.

Can the same be said about the EMF?
 
  • #10
DaveC426913 said:
Yes.

Can the same be said about the EMF?
You can zero the electric potential because the signs can be opposite - half way between an electron and a positron, for example. You can only zero the gradient of the gravitational potential.
 
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  • #11
Doesn't inflation have something to say about this?
 
  • #12
256bits said:
Doesn't inflation have something to say about this?
Inflation is a phenomenon in the very early universe, needs general relativity to discuss, and gravitational potential is not defined in any situation where it is a relevant effect.
 
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  • #13
sophiecentaur said:
The majority of the mass of the Earth was 'somewhere else' before it got together to form the Earth. There has been a tiny amount of mass change due to Energy changes but we can ignore that here.
I'm not sure how "Advanced Cosmology" you want to go but there's a reasonable classical argument that says that every tiny piece of mass has always affected every other tiny piece of mass (back to the big bang, at least).
Taking that into account, do you want to elaborate on your question?
(I see that I have more or less repeated what Dave has already written but the fact that we came up with similar answers should help to convince you! :smile: )

Sorry if I'm bothering, but can I ask, how exactly has every particle always affected every other particle, back to the big bang? I know I said I understood but now that I thought about it for a bit, I'm confused.
 
  • #14
TheQuestionGuy14 said:
Sorry if I'm bothering,
Not a bother. That's what we're here for.

TheQuestionGuy14 said:
but can I ask, how exactly has every particle always affected every other particle, back to the big bang?
The Big Bang started from a very small, dense state - all the mass was very close together - within each others' gravitational influence. The actual details are a bit more complicated but that's the gist.
 
  • #15
TheQuestionGuy14 said:
how exactly has every particle always affected every other particle, back to the big bang?
Gravity works that way. It never dies down to nothing.
The force per unit mass (g) is
g= Gm1 m2/d2
which is the good old inverse square law, with G being the universal gravitational constant, the m's are the masses and d is the distance between. Gravity always causes an attractive force between all pairs of masses and all the forces add up (multiple vectors adding together). As the formula shows you, it goes on for 'ever' - in the classical world. The details will change with modern theories about the geometry of the universe but this a very good start at understanding the system.
 
  • #16
DaveC426913 said:
Not a bother. That's what we're here for.The Big Bang started from a very small, dense state - all the mass was very close together - within each others' gravitational influence. The actual details are a bit more complicated but that's the gist.

sophiecentaur said:
Gravity works that way. It never dies down to nothing.
The force per unit mass (g) is
g= Gm1 m2/d2
which is the good old inverse square law, with G being the universal gravitational constant, the m's are the masses and d is the distance between. Gravity always causes an attractive force between all pairs of masses and all the forces add up (multiple vectors adding together). As the formula shows you, it goes on for 'ever' - in the classical world. The details will change with modern theories about the geometry of the universe but this a very good start at understanding the system.

So when the universe expanded after the big bang, did all the particles stay in every other particles gravitational field? They didn't leave the fields?
 
  • #17
TheQuestionGuy14 said:
So when the universe expanded after the big bang, did all the particles stay in every other particles gravitational field? They didn't leave the fields?
I see where you're going.

Since the Inflationary Epoch expanded at a rate greatly exceeding the speed of light - and gravitational waves only propagate at the speed of light - is it not possible that portions of the universe were isolated from each other?

Sure, but our observable universe is defined as only that portion in which all parts are within reach of each other.
Gravitational waves travel at the same speed as - and thus reaches as far as - light. i.e. If we can see light from it, then it affects us gravitationally.

As always, see sig line:*
 
  • #18
DaveC426913 said:
I see where you're going.

Since the Inflationary Epoch expanded at a rate greatly exceeding the speed of light - and gravitational waves only propagate at the speed of light - is it not possible that portions of the universe were isolated from each other?

Sure, but our observable universe is defined as only that portion in which all parts are within reach of each other.
Gravitational waves travel at the same speed as - and thus reaches as far as - light. i.e. If we can see light from it, then it affects us gravitationally.

As always, see sig line:*

Ah, I see. So, correct me if I'm wrong, but every particle in the observable universe has always been affected by every other particles gravity. Would I be correct?
 
  • #19
TheQuestionGuy14 said:
Ah, I see. So, correct me if I'm wrong, but every particle in the observable universe has always been affected by every other particles gravity. Would I be correct?
I reckon so.
 
  • #20
TheQuestionGuy14 said:
Sorry if I'm bothering, but can I ask, how exactly has every particle always affected every other particle, back to the big bang?
To varying amounts, most of them negligible.
 
  • #21
sophiecentaur said:
I reckon so.

And currently, space is expanding at an accelerating rate, doesn't that mean objects within the observal universe will eventually leave it and no longer be casually connected to Earth, meaning they'd leave Earth's gravitational field? What will happen to their (teeny tiny amount of) gravitational potential energy?
 
  • #22
TheQuestionGuy14 said:
And currently, space is expanding at an accelerating rate, doesn't that mean objects within the observal universe will eventually leave it and no longer be casually connected to Earth, meaning they'd leave Earth's gravitational field?
Yes, I believe so.

TheQuestionGuy14 said:
What will happen to their (teeny tiny amount of) gravitational potential energy?
It will reach zero - as intuited by the fact that such an object will no longer be tugged upon by the Earth.
 
  • #23
DaveC426913 said:
Yes, I believe so.It will reach zero - as intuited by the fact that such an object will no longer be tugged upon by the Earth.

I see, but wouldn't it reading zero mean it lost its potential energy?
 
  • #24
TheQuestionGuy14 said:
I see, but wouldn't it reading zero mean it lost its potential energy?
Sure.
 
  • #25
DaveC426913 said:
Sure.

Sorry for all the questions, I'm just really interested.

So, I know we're talking in terms of Relativity now, with the expansion of the universe and stuff, and in relativity implies there is no global conservation of energy. But, doesn't this loss of potential energy violate local conservation of energy? If I was on a far away planet, about to leave Earth's gravitational field, and I had an extremely accurate and hypothetical device that could measure the potential energy a particle has, wouldn't I see it lose potential energy, violating local conservation of energy?
 
  • #26
TheQuestionGuy14 said:
... the expansion of the universe...

... local conservation of energy...

... a far away planet ...
If you are so far away from the Earth that you are about to be causally disconnected from it, then we are not talking local effects, are we? We are talking effects of the scale of cosmological expansion. So where's the problem?
TheQuestionGuy14 said:
about to leave Earth's gravitational field, and I had an extremely accurate and hypothetical device that could measure the potential energy a particle has, wouldn't I see it lose potential energy, violating local conservation of energy?
Just like if you were on your planet observing Earth with a powerful telescope. Earth is at the very edge of your observable universe. It is hugely red-shifted and extremely dim.

If you wait at your scope for enough eons, you will see Earth's light eventually fade to nothing. Does that give you as much cause for concern as gravitational potential doing the same thing?
 
  • #27
Correct me if I'm wrong, but "gravitational potential energy" is not "stored" inside an object like electricity inside a battery (crude concept analogy, sorry.) Ex: the bowling ball resting on a shelf has gravitational potential energy only because of the proximity of the Earth. If the Earth is not present, that potential energy is not present either.
 
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  • #28
Yes. The energy is 'in the system'.
 

Related to How does gravitational potential energy work?

1. What is gravitational potential energy?

Gravitational potential energy is the energy that an object possesses due to its position in a gravitational field. It is the potential to do work by virtue of an object's position in a gravitational field.

2. How is gravitational potential energy calculated?

The formula for calculating gravitational potential energy is PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object relative to a reference point.

3. What affects the amount of gravitational potential energy an object has?

The amount of gravitational potential energy an object has is affected by its mass, the strength of the gravitational field it is in, and its height or distance from the reference point.

4. Can gravitational potential energy be converted into other forms of energy?

Yes, gravitational potential energy can be converted into other forms of energy such as kinetic energy or thermal energy. For example, when an object falls from a height, its gravitational potential energy is converted into kinetic energy as it gains speed.

5. How does gravitational potential energy affect objects in orbit?

Objects in orbit have a constant amount of gravitational potential energy because they are constantly moving at a constant distance from the center of the gravitational field. This energy is balanced by the kinetic energy of the object, keeping it in a stable orbit.

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