How Does Heat Addition Change the Temperature of an Ideal Gas?

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Homework Help Overview

The problem involves an ideal monatomic gas with a specific initial temperature and the addition of heat and work. Participants are discussing how these factors influence the final temperature of the gas.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Some participants express uncertainty about the relevant equations and their application to the problem. There is a discussion about the relationship between internal energy and temperature, particularly in the context of an ideal gas.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem. Some guidance has been offered regarding the specific heat of the gas and its implications for the relationship between heat, work, and temperature change.

Contextual Notes

Participants are considering the assumptions of ideal gas behavior and the specific heat capacity relevant to the problem. There is an acknowledgment of the need for clarity on how these concepts apply to the given scenario.

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Homework Statement


Three moles of an ideal monatomic gas are at a temperature of 345 K. Then, 2114 J of heat are added to the gas, and 811 J of work are done on it. What is the final temperature of the gas?


Homework Equations





The Attempt at a Solution


I have a feeling I'm missing an equation. I thought the equation was U = Q - W but that won't help me here.
 
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keemosabi said:
[

The Attempt at a Solution


I have a feeling I'm missing an equation. I thought the equation was U = Q - W but that won't help me here.
How is U related to temperature? Hint: what is the specific heat of a monatomic gas at constant volume (where W = 0 so Q = U)?

AM
 
Doesn't it depend upon the gas?
 
keemosabi said:
Doesn't it depend upon the gas?
Not if it is an ideal gas, which this is. The specific heat is Cv = 3R/2 where R is the universal gas constant (units are J/mole K). Since, by definition, \Delta Q = nC_v\Delta T and \Delta U = \Delta Q for a constant volume process and since U is a function only of T, it follows that

\Delta U = nC_v\Delta T[/itex]<br /> <br /> regardless of the type of process.<br /> <br /> AM
 

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