How Does Heat Expansion Affect Gas Temperature?

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SUMMARY

The discussion centers on the behavior of a monatomic ideal gas when heat is supplied, specifically at an initial temperature of 40°C. As the gas expands, its volume doubles and pressure decreases to half, leading to a final temperature calculation. The relevant equation used is the combined gas law, expressed as (P1V1)/(T1) = (P2V2)/T2. It is clarified that the gas absorbs heat from its surroundings during expansion, rather than gaining heat directly.

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  • Understanding of the ideal gas law and its variables (P, V, T).
  • Familiarity with the concept of monatomic ideal gases.
  • Knowledge of thermodynamic principles, particularly heat transfer.
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KingTutATL
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Heat is supplised to a sample of a monatomic ideal gas at 40C. It is observed that the gas expands until its volume is doubled and the pressure drops to half of its original value. What is the final temperature of the gas? How do you solve? pv=nRt R and n are constant so do you have (P1V1)/(T1)=(P2V2)T2?
 
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KingTutATL said:
Heat is supplised to a sample of a monatomic ideal gas at 40C. It is observed that the gas expands until its volume is doubled and the pressure drops to half of its original value. What is the final temperature of the gas? How do you solve? pv=nRt R and n are constant so do you have (P1V1)/(T1)=(P2V2)T2?
You've got it. The question is a bit confusing because the gas does not expand due to the supply of heat. It draws heat from its surroundings as it expands.

AM
 

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