Why does a gas behave as ideal if the Isotherm and Isenthelp

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Homework Help Overview

The discussion revolves around the behavior of gases, specifically why a gas behaves ideally when the Isotherm and Isenthalp are parallel. The subject area includes thermodynamics and properties of ideal gases.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between internal energy, temperature, and the behavior of ideal gases. Questions arise regarding the implications of parallel Isotherm and Isenthalp lines on internal energy.

Discussion Status

Some participants have offered insights into the relationship between internal energy and temperature for ideal gases, noting that internal energy remains constant if temperature is unchanged. However, there is still exploration of the implications of this relationship.

Contextual Notes

Participants are examining the definitions and assumptions related to internal energy in the context of ideal gas behavior, particularly in relation to specific thermodynamic processes.

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Homework Statement



Why does a gas behave as ideal if the Isotherm and Isenthalp are parallel.

Homework Equations


h=u+pv
T1=T2, P1V1=P2V2

The Attempt at a Solution


[/B]
h1=u1+p1v1, h2=u2+p2v2
h2=h1 so
u1+p1v1=u2+p2v2
and p1v1=p2v2
Does that mean internal energy for an ideal gas is zero?
I don't understand. Thanks in advance!
 
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No. It means that u1=u2
 
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Chestermiller said:
No. It means that u1=u2
Thanks! Why would internal energy be equal for an ideal gas process??
 
ScareCrow271828 said:
Thanks! Why would internal energy be equal for an ideal gas process??
For an ideal gas, the internal energy per unit mass is a unique physical property that depends only on the temperature, irrespective of the process. So, if the temperature is the same, the internal energy is the same.
 

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