How Does Hitting a Cue Ball Above the Equator Affect Its Motion?

AI Thread Summary
Hitting a cue ball above the equator introduces torque, affecting its spin and motion. The average force applied by the cue stick is 6000 N over a contact time of 20 microseconds. To determine the ball's speed after impact, one must consider both linear acceleration and the torque resulting from the off-center hit. The equations of motion, including F=Ma and the displacement formula, are relevant for calculating the ball's speed. Understanding the impact of the cue's contact point is crucial for accurate results.
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Homework Statement


A cue ball is hit 4.5 cm above the horizontal surface uk = 0.35 it is on.
The ball is 6 cm in diameter and has a mass of 250 g. It is hit
by a cue stick with an average force of
6000 N during a contact time of 20 usec.

(a) What is the ball’s speed after it is hit?

Homework Equations



F=Ma
x=x0+v0xt+1/2at^2

The Attempt at a Solution


I can't figure out the effect being hit above the equator has and how to incorporate it?
Thanks
 
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It sounds like they want you to take into account the torque on the cue ball due to the fact that it was hit off center. I guess you assume that the cue does not slip and that it hits parallel to the horizontal surface, but it doesn't actually say that, so I'm just guessing.
 

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