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How does kinetic energy change in circular motion?

  1. Dec 14, 2014 #1
    Could someone explain to me how the kinetic energy of a body moving in a circle is like? I got tempted it stays constant as the speed is constant but that turned out to be false.

    I am interested in places where the body is at top, side and bottom and so on. So I'd like to also know what the KE will be at those points...

    Thank you
     
  2. jcsd
  3. Dec 14, 2014 #2

    sophiecentaur

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    If the circle is in a horizontal plane then the KE will not change. If the circle is in a vertical plane then the gravitational potential at the top will be 2mgr (r is the radius) and zero at the bottom. The KE will vary in the opposite way - according to the gpe in any position, giving constant total energy throughout the rotation.
     
  4. Dec 14, 2014 #3
    Kinetic energy classically follows the following equation:
    $$
    KE = \frac{1}{2}mv^2
    $$
    Where m is mass, and v is velocity. Assuming it's vertical in a uniform gravitational field, the KE will be maximum at the bottom, and minimum at the top. At the left and right, it will be equal.
     
  5. Dec 14, 2014 #4
    Cool thanks for both answers.
     
  6. Dec 15, 2014 #5

    CWatters

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    That assumes the object isn't being forced to rotate at a constant speed. For example a pendulum trades off PE vs KE as it rotates but a DVD in a vertical DVD player doesn't.
     
  7. Dec 15, 2014 #6

    sophiecentaur

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    True. Except that, by definition, the KE cannot change if the speed remains the same. But the OP didn't specify clearly enough - this will happen if one doesn't know the subject well. A common PF problem.
     
    Last edited: Dec 15, 2014
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