How Does Mass Affect Acceleration and Deceleration in a Lorry?

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The discussion focuses on a physics homework assignment involving the acceleration and deceleration of a lorry, both unloaded and loaded with 800 kg of materials. Key calculations include determining the forces required for acceleration and braking, total time and distance traveled, and the percentage change in momentum between the two states. The original poster expresses confusion over their calculations, particularly regarding the acceleration of the loaded lorry, and seeks clarification on the problem's details. Additionally, there is a request for information about the electric field strength equation, indicating a broader interest in physics concepts. The conversation emphasizes the need for clear problem statements and accurate calculations in physics assignments.
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Homework Statement


Ok I have been given an assignment and asked to answer questions about a lorry loaded and unloaded. the Text is as follows:
An unloaded lorry of mass M kg accelerates from rest and reaches a velocity of 30mph in 10 seconds. It then travels at constant velocity for half a minute before the driver applies the brakes and brings the vehicle to rest over a distance of D m.
The lorry is then loaded with 800 kg of building materials that need to be transported over a total distance of 0.6 km. After loading, the lorry accelerates over a distance of 80m to attain a velocity of 30mph again. The vehicle subsequently maintains constant velocity before decelerating to rest at a rate of R m/s2.

M=2300KG D = 70m R = 1.5m/s^2

Homework Equations


The questions exactly
Find for the unloaded lorry:

i) the force required to accelerate the vehicle, and the retarding force necessary to bring it to rest;
ii) the total time and the total distance traveled during this period.

Find for the loaded lorry :

i) the force required to accelerate the vehicle and the retarding force necessary to bring it
to rest;

ii) the total time taken during this period and the distance traveled at constant velocity.

c) Calculate the % change in the momentum of the lorry from loaded to unloaded, whilst traveling at the specified constant velocities.

d) Draw the ‘velocity-time’ graph of the motion of the lorry in its unloaded and loaded states, indicating clearly salient points and values.

The Attempt at a Solution


I tried using V^2 = U^2 +2as , V=S/t and general thinking but I am 100% sure that I am incorect. i got answers like 0.65 m/s^2 which seemed possible but it is half the acceleration than when the lorry was unloaded, i think half is too little if only 800KG was added. i also got stupid answers like 15.67 m/s^2

can some one help me
 
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Read your own post again and you'll see why I can't understand it at all. What information is provided about the unloaded lorry? What's the actual question? Why does the 0.6 km matter?
 
I believe you left out some info regarding the unloaded lorry, like its acceleration, speed, etc. And you left out the question as well. Please re-write this problem in its entirety.
 
hey i edited the original message. i think i have got the full way to B) correctly. I need B to continue though, so you can see my de lima. I usually know what I am talking about when it comes to physics but this has really stumped me! any help is a positive result :)

Also does anyone know the value of e in the equation of electric field strength ( E = 1 / 4(pie) eo er x Q1Q2/r^2 )?
 
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