How does mg = ma follow from F=ma?

  • Thread starter Thread starter memsces
  • Start date Start date
  • Tags Tags
    F=ma
AI Thread Summary
Newton's second law, F=ma, indicates that the net force acting on an object equals its mass multiplied by its acceleration. In the specific scenario where gravity is the only force, this can be expressed as mg=ma, leading to the conclusion that g=a, meaning the acceleration of an object in free fall is equal to the acceleration due to gravity. However, real-world situations often involve additional forces like air resistance and friction, complicating the application of F=ma. Therefore, the equation typically represents the sum of all forces acting on an object. Understanding these principles is crucial for grasping the dynamics of motion.
memsces
Messages
3
Reaction score
0
Can somebody explain in simpler terms F=ma and why that can be writtent as mg=ma. Which finally can be written as g=a.
 
Physics news on Phys.org
memsces said:
Can somebody explain in simpler terms F=ma and why that can be writtent as mg=ma. Which finally can be written as g=a.
Newton's 2nd law states that the net force on an object must equal ma. In the special case where the only force on an object is gravity, which equals mg, then the net force is just mg. Thus mg = ma, which implies that g = a. (The acceleration of an object in free fall is g downwards.)
 
Doc_al is correct in saying that g = a when the object is in free fall (the only force acting on the object is gravity). However the world is not that simple, there are a lot more forces that can act on objects such as support force, air resistance, friction just to name a few. So therefore F=ma means the sum of all forces = ma, usually seen with the symbol sigma (meaning the sum of forces) before F. I hope that clarified things for you memsces.
 
Consider an extremely long and perfectly calibrated scale. A car with a mass of 1000 kg is placed on it, and the scale registers this weight accurately. Now, suppose the car begins to move, reaching very high speeds. Neglecting air resistance and rolling friction, if the car attains, for example, a velocity of 500 km/h, will the scale still indicate a weight corresponding to 1000 kg, or will the measured value decrease as a result of the motion? In a second scenario, imagine a person with a...
Scalar and vector potentials in Coulomb gauge Assume Coulomb gauge so that $$\nabla \cdot \mathbf{A}=0.\tag{1}$$ The scalar potential ##\phi## is described by Poisson's equation $$\nabla^2 \phi = -\frac{\rho}{\varepsilon_0}\tag{2}$$ which has the instantaneous general solution given by $$\phi(\mathbf{r},t)=\frac{1}{4\pi\varepsilon_0}\int \frac{\rho(\mathbf{r}',t)}{|\mathbf{r}-\mathbf{r}'|}d^3r'.\tag{3}$$ In Coulomb gauge the vector potential ##\mathbf{A}## is given by...
Dear all, in an encounter of an infamous claim by Gerlich and Tscheuschner that the Greenhouse effect is inconsistent with the 2nd law of thermodynamics I came to a simple thought experiment which I wanted to share with you to check my understanding and brush up my knowledge. The thought experiment I tried to calculate through is as follows. I have a sphere (1) with radius ##r##, acting like a black body at a temperature of exactly ##T_1 = 500 K##. With Stefan-Boltzmann you can calculate...

Similar threads

Replies
93
Views
2K
Replies
3
Views
2K
Replies
1
Views
2K
Replies
6
Views
1K
Replies
12
Views
1K
Replies
4
Views
3K
Replies
67
Views
5K
Back
Top