How Does Newton's 2nd Law Apply to Stopping Distance?

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SUMMARY

The discussion focuses on calculating the minimum stopping distance for a 1000 kg car traveling at 25 m/s with a braking force of 5000 N. Using Newton's second law, the acceleration is determined to be -5 m/s². The kinetic energy of the car, calculated as 312500 J, equates to the work done by the brakes, leading to the conclusion that the minimum stopping distance is 31.25 meters.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of kinematic equations
  • Familiarity with kinetic energy calculations
  • Basic grasp of work-energy principle
NEXT STEPS
  • Study the application of Newton's laws in real-world scenarios
  • Learn advanced kinematics for varying acceleration
  • Explore the work-energy theorem in different contexts
  • Investigate factors affecting braking distance, such as friction
USEFUL FOR

Physics students, automotive engineers, and anyone interested in the dynamics of vehicle motion and safety calculations.

tennisacerg
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Can you please help me out with this problem?!?

Suppose that a 1000 kg car is traveling at 25 m/s (about 55 mph). It brakes can apply a force of 5000 N. What is the minimum distance required for the car to stop.

:confused:
 
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acceleration=f/m
that's negative 5m/(ss)
Now the kinematics are easy--but ask if you need help.

Another approach is energy. Work to stop the car=car's kinetic energy=
(.5)(mass)(velocity squared)= (distance)(force by brakes)
 

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