How does one calculate the velocity and strengh of a whirlpool?

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Calculating the velocity and strength of a whirlpool depends on the scale and the amount of water involved. Larger whirlpools, such as those formed by natural disasters, can exert significant force, capable of capturing large objects like boats. In contrast, smaller whirlpools, like those in bathtubs, have much less pull but can still affect smaller items. Mathematical equations can be developed to describe these phenomena, taking into account factors like water volume and current. Understanding these principles is essential for accurately assessing whirlpool dynamics.
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For example the earthquake in Japan awhile back had the strength to capture a boat within it's pull. Yet the whirlpool created when someone pulls a plug on the bathtub is hardly any pull whatsoever. This may be a simplistic way of putting it, and i know it has to do with the amount of water and current. How would something like this be put into a mathematical equation too.

Thanks
 
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Niaboc67 said:
For example the earthquake in Japan awhile back had the strength to capture a boat within it's pull. Yet the whirlpool created when someone pulls a plug on the bathtub is hardly any pull whatsoever.
Thanks

thats purely a question of scale. The small whirlpool in a plughole in the tub will still pull in objects of a relative smaller size

Dave
 
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