thunderhadron
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Hi friends the problem is -
https://fbcdn-sphotos-e-a.akamaihd.net/hphotos-ak-ash4/430884_2656507629229_1511525381_n.jpg
Attempt -
friend as per the question I am trying to get structure of SHM,
The displacement equation x = A sin(ωt + θ) represents SHM where ωt + θ is Phase of the particle.
the phase of the particle is 13∏/6. So I putting it on the equation and getting the result -
x = A/2. So I am getting the first answer.
While differentiating the displacement equation w.r.t. time I'll get velocity - time equation.
Which will be,
v = A.ω cos(ωt + θ)
Placing here the Phase of the particle I am getting the result,
v = A.ω.√3 / 2
So i am sticking here, is it representing the direction of the particle too ?
The correct answer of this problem is option (A) as per the question.
Please friends help me in solving this Problem.
Thank you all in advance.
https://fbcdn-sphotos-e-a.akamaihd.net/hphotos-ak-ash4/430884_2656507629229_1511525381_n.jpg
Attempt -
friend as per the question I am trying to get structure of SHM,
The displacement equation x = A sin(ωt + θ) represents SHM where ωt + θ is Phase of the particle.
the phase of the particle is 13∏/6. So I putting it on the equation and getting the result -
x = A/2. So I am getting the first answer.
While differentiating the displacement equation w.r.t. time I'll get velocity - time equation.
Which will be,
v = A.ω cos(ωt + θ)
Placing here the Phase of the particle I am getting the result,
v = A.ω.√3 / 2
So i am sticking here, is it representing the direction of the particle too ?
The correct answer of this problem is option (A) as per the question.
Please friends help me in solving this Problem.
Thank you all in advance.