How Does Quadrant Location Affect the Electric Field Vector Calculation?

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SUMMARY

The discussion focuses on the calculation of the electric field vector R in relation to its quadrant location. The equation provided, R = -xaa - yay + 3az, is analyzed across four quadrants, yielding distinct expressions for R: R = +xaa - yay + 3az for the 1st quadrant, R = -xaa + yay + 3az for the 2nd quadrant, R = -xaa + yay + 3az for the 3rd quadrant, and R = -xaa - yay + 3az for the 4th quadrant. The confusion arises from the application of the equation to all quadrants, which is clarified by understanding that it represents the negative position vector from the origin to any point (x, y, -3) on the square sheet.

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azizlwl
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Homework Statement


From attachment R=-xaa-yay+3az

Homework Equations

The Attempt at a Solution


I see 4 different values, one for each quadrant.
1st.quadrant
R=+xaa-yay+3az
2nd. quadrant
R=-xaa+yay+3az
3rd.
R=-xaa+yay+3az
4th
R=-xaa-yay+3az

Where did I go wrong in determine value of R?

 

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The equation they gave applies to all 4 quadrants. It is just equal to minus a position vector drawn from the origin to any arbitrary point (x,y,-3) on the square sheet. The 3 unit vectors in their equation are pointing in the 3 positive coordinate directions.

Chet
 

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