How Does Rewinding a Coil Affect Its Self-Inductance and Energy Storage?

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Rewinding a coil with half the number of turns while maintaining the same diameter reduces its self-inductance to one-quarter of the original value. The relationship between self-inductance and the number of turns indicates that halving the turns results in a significant decrease in inductance. Additionally, when the current through an inductor is doubled, the energy stored in the inductor quadruples, as shown by the equation U = 0.5*L*I^2. The induced emf in a loop with a varying magnetic flux is calculated using the derivative of the flux equation, yielding 31 V when evaluated at t = 2 seconds. Overall, the calculations and concepts presented are accurate and demonstrate a solid understanding of inductance and energy storage principles.
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Homework Statement



After you measure the self-inductance of a coil, you unwind it and then rewind half the length of wire into a coil with the same diameter but half the number of turns. How does this change the self-inductance?

a. It is the same.
b. It is doubled.
c. It is quadrupled.
d. It is halved.
e. It is quartered.

Homework Equations



See below.


The Attempt at a Solution



L = (N* magnetic flux)/i = (N*B*A*cos theta)/i = (n*l*A*B*cos theta)/(i), where N = n*l (l = wire length)

L2 = [(l/2)*A*(n/2)*B]/i = (1/4)*[(L*A*n*B)/i] = (1/4)*L??



Homework Statement


How much does the energy stored in an inductor change if the current through the inductor is doubled?

a. It remains the same.
b. It is doubled.
c. It is quadrupled.
d. It is halved.
e. It is quartered.




Homework Equations



See below.

The Attempt at a Solution



U = 0.5*L*I^2

U2 = 0.5*L*(2I)^2 = 4*0.5*L*I^2 = 4*U??


Homework Statement



The magnetic flux through a loop is made to vary according to the relation magnetic flux = 6t^2 + 7t + 1, where the units are SI. The emf induced in the loop when t = 2 s is

a. 38 V
b. 39 V
c. 40 V
d. 31 V
e. 19 V


Homework Equations



Emf_induced = -(d magnetic flux)/(dt)

The Attempt at a Solution



Taking the derivative, |emf| = 12t + 7, where t = 2 s

|Emf| = 12*(2s) + 7 = 31 V??

Thanks.
 
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You don't seem to be having any problems with this. They all look correct.
 
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