How Does Static Friction Determine a Car's Maximum Acceleration?

Click For Summary
SUMMARY

The maximum acceleration of a car is determined by the coefficient of static friction, which in this case is 0.38. The relationship between force, mass, and friction is established through the equation F = ma, where the frictional force (Ffr) is calculated as the product of the static friction coefficient and the normal force (Fn). Since mass is not provided, it cancels out in the calculations, allowing for a direct relationship between the static friction and maximum acceleration without needing specific mass values.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of static friction and its coefficient
  • Familiarity with normal force concepts in physics
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the relationship between static friction and acceleration in different scenarios
  • Learn how to calculate normal force in various contexts
  • Explore the implications of friction in vehicle dynamics
  • Investigate the effects of different coefficients of friction on vehicle performance
USEFUL FOR

Physics students, automotive engineers, and anyone interested in understanding vehicle dynamics and the role of friction in acceleration.

Hailcanadien
Messages
7
Reaction score
0

Homework Statement


What is the maximum acceleration a car can undergo if the coefficient of static friction between the tires and the ground is 0.38?

that is it, no mass or anything else

Homework Equations


F=ma
(friction coefficient)Fn=Ffr
Fn = normal force
Ffr = friction force


The Attempt at a Solution


I have tried different things, but I can't figure out how to do the problem without a mass...
 
Physics news on Phys.org
Show your calculations.
The car will start moving when the applied force overcomes the frictional force.
 
Hailcanadien said:
1.
I have tried different things, but I can't figure out how to do the problem without a mass...


The fact that no mass is given should be a clue. In other words you can expect that the mass of the car will cancel from the equation you want to develop.

The previous hint was not quite correct. In essence you can think of the car being the car is accelerated by any force less than, or just equal to the static frictional force between the tires and the road. Above that and the tires will spin causing rubber to be burned and the car accelerates more slowly.

Hence you need to combine F = ma and your equation for the frictional force. Remember that the frictional force is given by the coefficient of static friction times the normal force. What is the normal force? There you will find a mass that will cancel the m in F = ma.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
17
Views
2K
Replies
11
Views
1K
Replies
15
Views
2K
Replies
42
Views
2K
Replies
12
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K