How Does the Chain Rule Relate to Tangent Vectors in Calculus?

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silverwhale
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Homework Statement



Show that:

[tex]\frac{dx^\nu}{d \lambda} \partial_\nu \frac{dx^\mu}{d \lambda} = \frac{d^2 x^\mu}{d \lambda^2}[/tex]



The Attempt at a Solution



Well, I could simply cancel the dx^nu and get the desired result; that I do understand.
But what about actually looking at this term alone:

[tex]\partial_\nu \frac{dx^\mu}{d \lambda},[/tex]

calculating it and multiplying with dx^nu/dλ, can I get the same result? I get confused by the question: what if the partial derivative acts on the tangent vector; what happens then?


Thanks for your help!
 
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The problem is that [itex]\frac{d}{d\lambda}[/itex]and [itex]\partial_\mu[/itex] do not commute... So I'm not sure how you could calculate it without knowing what [itex]\frac{d}{d\lambda}[/itex] is.