How Does the Delta Function Simplify Integral Equations in Arken's Text?

  • Thread starter Thread starter Hariraumurthy
  • Start date Start date
  • Tags Tags
    Integral
Click For Summary
SUMMARY

The discussion focuses on the simplification of integral equations using the delta function as presented in Arken's text. Specifically, it addresses the transition from equation 16.9 to 16.6 under the condition where \( v(\vec{r}, \vec{r'}) = v(\vec{r})\delta(\vec{r} - \vec{r'}) \). The participants clarify that the integral involving the delta function can be evaluated directly without integration by parts, leading to the conclusion that the right-hand side reduces correctly to \( v(\vec{r})\psi(\vec{r}) \) when \( \vec{r} \) is within the region of integration \( \Omega \). Additionally, the boundary conditions regarding \( \partial \Omega \) are discussed, with indications that they are fixed.

PREREQUISITES
  • Understanding of integral equations, specifically Fredholm equations of the second kind.
  • Familiarity with the delta function and its properties in mathematical analysis.
  • Knowledge of vector calculus, particularly the Laplacian operator \( \nabla^2 \).
  • Basic skills in integration techniques, including integration by parts.
NEXT STEPS
  • Study the properties of the delta function in detail, focusing on its role in integral equations.
  • Explore Fredholm equations of the second kind and their applications in mathematical physics.
  • Learn about the Laplacian operator and its significance in solving partial differential equations.
  • Review integration techniques, particularly integration by parts and their implications in vector calculus.
USEFUL FOR

Students and researchers in mathematics, physics, and engineering who are working with integral equations, particularly those utilizing the delta function in their analyses.

Hariraumurthy
Messages
14
Reaction score
0

Homework Statement


I am trying to read arken's section on integral equations because I need it for a problem I am trying to attack. I am stuck on a part of a page. I have attached the relevant excerpt from the book.(Not the whole book because it is copyrighted)


Homework Equations



I am stuck on equation 16.9. That is I am not sure how for the special case of [tex]v\left( {\vec r,\vec r'} \right) = v\left( {\vec r} \right)\delta \left( {\vec r - \vec r'} \right)[/tex], that
[tex]\left( {{\nabla ^2} + {a^2}} \right)\psi \left( {\vec r} \right) = \int {v\left( {\vec r,\vec r'} \right)} \psi \left( {\vec r} \right){d^3}\left( {r'} \right)[/tex] reduces to [tex]\left( {{\nabla ^2} + {a^2}} \right)\psi \left( {\vec r} \right) = v\left( {\vec r} \right)\psi \left( {\vec r} \right)[/tex]
when

The Attempt at a Solution


If [tex]{\vec r}[/tex] is in the region of integration [tex]\Omega[/tex] (case 1), then using integration by parts, the reduced RHS is given by [tex]\int\limits_\Omega ^{} {v\left( {\vec r'} \right)\psi \left( {\vec r'} \right)} \delta \left( {\vec r - \vec r'} \right){d^3}\left( {r'} \right) = {\left[ {v\left( {r'} \right)v(r')} \right]_\Omega } - \int_\Omega ^{} d \left( {v\left( {\vec r'} \right)\psi \left( {\vec r'} \right)} \right)[/tex] since in general the integral of [tex]\delta \left( {\vec x} \right)[/tex] over any region containing [tex]\vec x = 0[/tex] is 1. The second integral [tex]\int_\Omega ^{} d \left( {v\left( {\vec r'} \right)\psi \left( {\vec r'} \right)} \right)[/tex] is just [tex]{\left[ {v\left( {r'} \right)v(r')} \right]_\Omega }[/tex]. Therefore the RHS is 0 which is not the LHS.

Case 2: [tex]\vec r \notin \Omega[/tex]. Doing the same integration by parts, the reduced RHS is
[tex]{\left[ {v\left( {r'} \right)v(r')} \right]_\Omega }\int_\Omega ^{} {\delta \left( {\vec r - \vec r'} \right)} {d^3}\left( {r'} \right) - \int_\Omega ^{} {\left( {\left( {\int_\Omega ^{} {\delta \left( {\vec r - \vec r'} \right){d^3}\left( {r'} \right)} } \right)d\left( {v\left( {\vec r'} \right)\psi \left( {\vec r'} \right)} \right)} \right)} = 0 - 0 \ne RHS[/tex].

In summary I am having trouble verifying that for the special case of 16.9, 16.8 reduces to 16.6.

Also is [tex]\partial \Omega[/tex] fixed or not?(my guess is that the boundary is fixed because Arken transforms this into a fredholm equation of the second kind later on in the page(included in the excerpt.)

Thanks in advance for replying.
 

Attachments

Physics news on Phys.org
Hello,

You simply have to consider that

[itex]\int_{\Omega}\mathrm{d}x f(x) \delta(x) = f(0) \; \mathrm{if} \; 0\in \Omega, \mathrm{or} =0 \; \mathrm{if} \; 0\notin\Omega[/itex];

no integration by parts is needed :)

Ilm
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 15 ·
Replies
15
Views
1K