How Does the Ideal Gas Law Apply to Chemical Reactions?

Click For Summary
SUMMARY

The discussion centers on the application of the Ideal Gas Law (PV=nRT) to a chemical reaction involving gases, specifically the reaction 2A(g) + 3B(g) -> 4C(g). Key conclusions include that as the number of moles decreases from 5 to 4, the temperature increases at constant pressure and volume, while volume and pressure decrease. The density of the gas mixture increases at constant temperature and pressure, leading to a distinction between mass density and molar density. The participants confirm the reasoning behind the changes in these variables based on the Ideal Gas Law.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV=nRT)
  • Knowledge of chemical reaction stoichiometry
  • Familiarity with concepts of density and molar density
  • Basic principles of thermodynamics related to gas behavior
NEXT STEPS
  • Explore the implications of the Ideal Gas Law in different thermodynamic processes
  • Study the relationship between density and molar mass in gases
  • Investigate the concept of molar density versus mass density in chemical reactions
  • Learn about the effects of temperature and pressure changes on gas behavior
USEFUL FOR

Chemistry students, educators, and professionals involved in chemical engineering or thermodynamics who seek to deepen their understanding of gas behavior in reactions.

Qube
Gold Member
Messages
461
Reaction score
1

Homework Statement



1. When the following reaction proceeds, what will be true? 2A(g) + 3B(g) -> 4C(g)

(1) The temperature will increase at constant P and V.
(2) The volume will increase at constant T and P.
(3) The pressure will increase at constant T and V.
(4) The density will increase at constant T and P.
(5) The moles will increase at constant T and V.


Homework Equations



PV=nRT

The Attempt at a Solution



PV=nT. I removed the constant R. This is the equation I'll be considering when evaluating how each variable in the ideal gas equation is related to another variable.

We know from the equation in the question that the number of moles of gas decreases from 5 to 4. There are 5 moles of reactants and 4 moles of products. So n changes.

The choices present one variable as increasing along with two other variables held constant. So let's consider the choices.

1) Temperature will increase if P and V are held constant. Temperature is INVERSELY proportional to n. N decreases. T increases. Yes. Well, that was quick, but let's consider the other choices.

2) Volume is directly proportional to n because the two variables are on opposite sides of the equation PV=nRT and there aren't any fractions. N decreases. V also decreases. We can generalize this rule: any variable directly proportional to n will decreases as n is decreasing and if this variable decreases this variable will contradict any answer choices (since they all peg the variable as increasing).

3) P is directly proportional to n. Wrong choice in the context of the problem.

4) Density = Molar Mass (M) multiplied by P (pressure) over RT, where R is the gas constant and T is temperature. T and P are held constant, so looks like density is proportional to molar mass. We don't know any molar masses. The identities of the gases is unknown. Can't be right.

5) This directly contradicts what's going on in the problem in the first place.

Questions:

1) I'm fairly confident my answer is correct; are my lines of reasoning similarly correct?

2) Also this is a test question from a test I just took and this question got thrown out without explanation. Any answer choice chosen was considered correct. Why might this be? Am I overlooking something?
 
Physics news on Phys.org
The only thing I can think of is #4. You already correctly said in #2 that, at constant T and P, the volume decreases. Irrespective of the molar masses, the total mass of material in the reactor doesn't change. So the mass density must increase. However, if you are referring to the molar density, the volume decreases in proportion to the number of moles. So the molar density doesn't change.
 
  • Like
Likes   Reactions: 1 person
Thanks! Prof agreed. There is an argument to be made regarding molar density and mass density.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
9
Views
3K
Replies
1
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K