How does the spring scale read in different elevator scenarios?

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In an elevator moving at a constant upward or downward speed, a spring scale will read the weight of the woman, which is 58 kg multiplied by gravity (approximately 568 N). When the elevator accelerates upward at 0.33g, the scale will read a higher value due to the additional force from the acceleration. Conversely, during downward acceleration of 0.33g, the scale will read a lower value as the effective weight decreases. In free fall, the scale will read zero because the woman experiences weightlessness. Understanding these principles involves applying Newton's second law, where force equals mass times acceleration.
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What will a spring scale read for teh weight of a 58 kg woman in an elevator that moves (a) with a constant upward speed of 6.0 m's, (b) with a constant downward speed of 6.0 m/s, (c) with upward acceleration of 0.33g, (d) with downward acceleration of 0.33g, and (e) in free fall?

I'm having trouble with a and b. (c and d are easy enough because the g is given and e is weightless because it's free fall.) I don't know where to start!
 
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Force equals mass times acceleration. The scale will read the weight of the woman (NOT mass)

plus her mass times acceleration upward.

minus her mass times acceleration downward.

with no acceleration (just constant speed) the scale will read her weight.

In free fall, mass times downward acceleration equals weight so there would be no reading.
 
The balance provides all the tension to the man,R.
That's to say, R-F=net force
 
primarygun said:
The balance provides all the tension to the man,R.
That's to say, R-F=net force

But there was no man!
 
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