How Does the Work-Energy Theorem Determine the Initial Speed of a Sledgehammer?

AI Thread Summary
The discussion revolves around calculating the initial speed of a sledgehammer using the work-energy theorem, given that 490 J of work is done on it. The equation used is (Fnet)(d) = (0.5)(m)(velocity final^2 - velocity initial^2). The user encounters confusion with the negative value for initial velocity when solving the equation, leading to questions about the direction of forces and work done. Clarification is provided that the net force on the hammer acts upwards against its downward displacement, indicating negative work done on the hammer. Ultimately, the correct initial speed of the sledgehammer is confirmed to be 14 m/s.
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Homework Statement



490 J of work is done on a pin when a 5 kg sledgehammer strikes it (bringing the sledgehammer to rest). What is the initial speed of the sledge hammer.


Homework Equations



(Fnet)(d)= (0.5)(m)(velocity final^2 - velocity initial^2)


The Attempt at a Solution



490 = (0.5)(5)(0^2 - v inital^2)
980 = 5 (-v initial^2)
196 = - v initial^2


Problem is, v initial is now negative, and to get rid of the negative, I'd have to divide both sides by -1. But then it would be -196, and I would not be able to square root that. The answer is already given, and it is 14 m/s. It's just that one problem that has me stuck.

Help much appreciated :)
 
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The net force on the pin acts upward, and the displacemnt is downward, so the total work done of 490 J is positive or negative?
 
It would be negative.
But how is the net force on the pin acting upwards?
 
aishax said:
It would be negative.
But how is the net force on the pin acting upwards?

I think PhantomJay meant that the net force on the hammer is upwards, which is opposite to its displacement (hence the negative work done on the hammer and negative change in its kinetic energy).
 
Ahh, okay. That makes sense.
Thank you! :)
 
cepheid said:
I think PhantomJay meant that the net force on the hammer is upwards
Yes, thanks for the correction.
 
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