How Does Torque Affect the Stopping Time of a Potter's Wheel?

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SUMMARY

The discussion focuses on calculating the torque exerted by a potter on a wheel and determining the stopping time of the wheel. The torque is calculated using the formula Torque = Force x Radius, resulting in a torque of 0.09 Nm when a frictional force of 1.5 N is applied at a radius of 0.06 m (diameter of 12 cm). To find the stopping time, the relationship between torque, moment of inertia (0.11 kg*m²), and angular acceleration is utilized, leading to the conclusion that the potter must apply these principles to derive the time it takes for the wheel to cease rotation.

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  • Knowledge of moment of inertia and its significance in rotational motion
  • Basic proficiency in algebra for rearranging equations
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  • Study the relationship between torque and angular acceleration in rotational dynamics
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This discussion is beneficial for physics students, mechanical engineers, and anyone interested in understanding the principles of rotational motion and torque calculations.

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A potter is shaping a bowl on a potters wheel rotating at constant angular speed. The frictional force between her hands and the clay is 1.5N total. A. How large is her torque on the wheel, if the diameter of the bowl is 12 cm? B. How long would it take for the potters wheel to stop if the only torque acting on it is due to the potters hand? The initial angular velocity of the wheel is 1.6 rev\s, and th moment of inertia of the wheel and the bowl is 0.11kg*m^2.

So part A is just the force times the radius right? ie. 1.5N*.06m=.09Nm. Part B is my sticking point. I'm not really sure where to go from here.
 
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For Part B, you need to use the equation for torque: Torque = Moment of Inertia x Angular AccelerationYou can rearrange this equation to solve for the angular acceleration given the torque and the moment of inertia. Then, use the equation for angular velocity given angular acceleration and initial angular velocity to solve for the time it takes for the wheel to stop.
 

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