How Does Work Done on a Car Relate to Its Kinetic Energy and Speed?

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Homework Help Overview

The discussion revolves around a physics problem involving a car's kinetic energy and the work done on it by a force. The original poster presents a scenario where a car of mass 800 kg is acted upon by a force of 2000 N over a distance of 5 m, while also noting the restriction against using SUVAT equations.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between work done and kinetic energy, with some attempting to calculate the work done using the formula for work. Questions arise regarding the application of the work-energy theorem and the implications of the work done on the car's kinetic energy.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on using the work-energy theorem. There is a mix of understanding and confusion regarding the concepts involved, particularly around the relationship between work and kinetic energy.

Contextual Notes

The original poster is constrained by the requirement not to use SUVAT equations, which adds complexity to their approach. Additionally, there is uncertainty about the application of the work-energy theorem and its implications for the problem at hand.

HopelessMe
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1. A car of mass 800kg is at rest. The engine exerts a resultant force of 2000 N for a distance of 5m. a) What is then its kinetic energy? b) What is then its speed?



2. It is required that you must not use any SUVAT equations while solving this problem.

Possible equations to use are:
kinetic energy = 1/2 x m x v^2
Gravitational Potential Energy = m x g x h
Work = force x distance
F = m x a
W = m x g



3. I have attempted this question a number of times as I'm trying to find the velocity, but since there is no height in this question, I can't use the GPE equation, I'm just a little bit confused and would really appreciate some help.
 
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Hi HopelessMe! Welcome to PF! :smile:

Try work = force x distance. :wink:

(btw, strictly, it's force "dot" displacement)
 
Force x distance = 2000 N x 5 m = 10000 J

Okay, how do I use 10 000 J :shy:
 
Do you know the work energy theorem? :smile:
 
tiny-tim said:
Do you know the work energy theorem? :smile:

Hey Tiny-Tim,

I don't believe I'm aware of the theorem. I know that work is the energy that's been changed from one form to another... :confused:
 
So do you mean to say that the work done is equal to the kinetic energy?:eek:
 
HopelessMe said:
So do you mean to say that the work done is equal to the kinetic energy?:eek:

work done equals the increase in mechanical energy …

that's kinetic energy plus various forms of potential energy​

(haven't your lectures covered this?

if not, look it up)
 

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