How far apart are the stations?

  • Thread starter Thread starter Starrrrr
  • Start date Start date
AI Thread Summary
The discussion revolves around calculating the distance between two train stations based on a train's journey involving acceleration, constant speed, and deceleration. The train accelerates at 0.3 m/s² for 3 minutes, maintains maximum speed for 5 minutes, and then decelerates at -2 m/s² until it stops. Participants emphasize the need to calculate the distances for each segment of the journey separately rather than subtracting values. The final distance calculated by multiple users is 21,789 meters, confirming the solution's accuracy. The conversation highlights the importance of understanding motion equations and segmenting the journey for accurate distance measurement.
Starrrrr
Messages
38
Reaction score
2
1.
A train leaves a station from rest with a constant acceleration of 0.3m/s2. It reaches a maximum speed after 3 minutes and maintains this speed for a further 5 minutes, when it slows down with a deceleration −2 m/s2 until it comes to rest at the next station. How far apart are the stations?


2.
s=1/2(a)(t)^2
s2-s1 or s1-s2 not sure.

The Attempt at a Solution

: a1=0.3ms^-2 t1=180s a2=-2ms^-2 t2=300s
Then I used the s=1/2at^2 formula and found that s1=4860m and s2=-90000m
This is the part I'm stuck on is it s2-s1 or s1-s2 to find how far apart the stations are?[/B]
When I use the s2-s1 it gives me a negative value and I think there is no such thing as a negative distance.
 
Physics news on Phys.org
There are three portions of the trip, not just two.

The equation ##s=\frac{1}{2}at^2## only applies if certain conditions are met. What are some of those conditions?

Edit: I may have misunderstood your difficulty. The approach that I have in mind is adding up the distance for the three segments of the journey, not subtracting.
 
I have been trying to find the third trip but I still don't understand.
 
There are 3 segments of the trip that you need to calculate individually. The first segment is where the train is accelerating during the whole segment. The second segment is where the train is moving at constant velocity during the whole segment. The third segment is where the train is decelerating during the whole segment. The distance between the two stations is the sum of those three distances: s1 + s2 + s3
 
  • Like
Likes Starrrrr
TomHart said:
There are 3 segments of the trip that you need to calculate individually. The first segment is where the train is accelerating during the whole segment. The second segment is where the train is moving at constant velocity during the whole segment. The third segment is where the train is decelerating during the whole segment. The distance between the two stations is the sum of those three distances: s1 + s2 + s3
ok thanks ill try and solve it, I have been doing this question for 3 hours, the funny thing is I find the hardest qs easy and easy qs hard :D
 
I got an answer of 21789m if anyone can verify please.
 
I got the same result.
 
  • Like
Likes Starrrrr
TomHart said:
I got the same result.
Ok thank you sooo much. ;)
 
  • Like
Likes TomHart
Back
Top