MHB How Far Does a Car Travel in 10 Seconds at a Constant Acceleration of 2.0 m/s^2?

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A car accelerating from rest at a constant rate of 2.0 m/s² will travel 100 meters in 10 seconds. The calculation uses the formula d = vt + 1/2 at², where initial velocity (v) is 0, acceleration (a) is 2 m/s², and time (t) is 10 seconds. Substituting these values confirms the distance traveled is indeed 100 meters. The discussion emphasizes the straightforward application of the formula for calculating distance under constant acceleration. Understanding this concept is essential for mastering basic physics principles related to motion.
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A car, start from rest, accelerates in straight line at a constant rate of $2.0 m/s^2$
How far will the car travel in 10 seconds
use
$d=vt+\dfrac{1}{2}at^2\quad v=0\quad a=2\,m/s^2\quad t=10$
then
$$d=(0)(10\, s)
+\dfrac{1}{\cancel{2}}\left(\dfrac{\cancel{2}m}{\cancel{s^2}}\right)(10^2\cancel{s^2})
=100\, m$$

ok I know this relatively easy but it still new to me so hopefully ok
 
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Yes, since you are given that formula, it is just a matter of putting the given numbers into the formula and doing the arithmetic. The distance traveled in 10 seconds is, as you say, 100 meters.

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