How Far Does a Car Travel in 10 Seconds at a Constant Acceleration of 2.0 m/s^2?

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A car accelerating from rest at a constant rate of 2.0 m/s² travels a distance of 100 meters in 10 seconds. The calculation is based on the formula d = vt + (1/2)at², where initial velocity (v) is 0, acceleration (a) is 2.0 m/s², and time (t) is 10 seconds. Substituting these values into the equation confirms that the distance covered is indeed 100 meters.

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karush
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A car, start from rest, accelerates in straight line at a constant rate of $2.0 m/s^2$
How far will the car travel in 10 seconds
use
$d=vt+\dfrac{1}{2}at^2\quad v=0\quad a=2\,m/s^2\quad t=10$
then
$$d=(0)(10\, s)
+\dfrac{1}{\cancel{2}}\left(\dfrac{\cancel{2}m}{\cancel{s^2}}\right)(10^2\cancel{s^2})
=100\, m$$

ok I know this relatively easy but it still new to me so hopefully ok
 
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Yes, since you are given that formula, it is just a matter of putting the given numbers into the formula and doing the arithmetic. The distance traveled in 10 seconds is, as you say, 100 meters.

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