How Far is the Satellite from Earth's Surface?

AI Thread Summary
The discussion revolves around calculating the distance of a satellite from Earth's surface, given the Earth's radius and mass, along with the gravitational acceleration at the satellite's location. Participants emphasize the importance of equating gravitational force with centripetal force to solve the problem. Clarification is provided that the mass of the satellite is not needed for the calculation, as it cancels out in the equations. The key equation used is 3.2 = G(5.98e24)/R^2, which participants confirm can be solved for R. Understanding the context of R in the equation is highlighted as crucial for finding the satellite's altitude.
Rbethell16
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Homework Statement


The radius of the Earth is 6.86 e6 m and the mass of the Earth is 5.98 e24kg. There is a satellite floating in space at a point where the Earth's gravitational acceleration is 3.2 m/s^2.

How far above the Earth's surface is the satellite?


Homework Equations


Fg = Gmm/r^2


The Attempt at a Solution


I know I need to find Fg - at least I think. But I don't know how to start...
 
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Rbethell16 said:

Homework Equations


Fg = Gmm/r^2

The Attempt at a Solution


I know I need to find Fg - at least I think. But I don't know how to start...
The gravitational force of attraction provides the centripetal force. So you need to equate Fg and Fcentripetal (which you can just write as ma for this case).
 
rock.freak667 said:
The gravitational force of attraction provides the centripetal force. So you need to equate Fg and Fcentripetal (which you can just write as ma for this case).

ma - ok, I have the acceleration, but I get confused as to which "m" i am using. My problem is the intuition with formulas
 
Wow I reread the problem and I am extra confused. How do I figure out the mass of the shuttle?
 
Rbethell16 said:
Wow I reread the problem and I am extra confused. How do I figure out the mass of the shuttle?

You don't need it! if you have

ma= GMm/r2

an 'm' (the mass of the shuttle) cancels out :wink:
 
Ahhh so 3.2 = G(5.98e24)/R^2. Then solve for R?
 
Rbethell16 said:
Ahhh so 3.2 = G(5.98e24)/R^2. Then solve for R?

Yes, but be aware of what that R is.
 
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