How Fast Does the Shadow Move on a Dome as a Balloon Rises?

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Homework Help Overview

The problem involves a hemispherical dome with a diameter of 100m and a searchlight positioned at the center. A balloon rises vertically at a speed of 4m/s, and the task is to determine how fast the shadow of the balloon moves along the dome's surface as it ascends 25m.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the nature of the shadow and its relationship to the geometry of the dome. Some express confusion about how the shadow behaves and the relevance of the balloon's velocity. Others explore the relationship between the height of the balloon and the angle of the shadow.

Discussion Status

Several participants are actively engaging with the problem, attempting to derive relationships between the variables involved. There is a recognition of the need to incorporate the balloon's velocity into the calculations, but uncertainty remains regarding how to effectively use it. Some have made progress in formulating equations but are still seeking clarity on specific angles and time variables.

Contextual Notes

Participants note the absence of time information, which complicates the calculations. The problem setup and the geometry of the dome are central to the discussion, with some questioning assumptions about the shadow's movement along the dome's surface.

Myung
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Homework Statement



A hemispherical dome has a diameter of 100m. A search light was placed at point A as shown at the middle of the dome at B. A balloon was released vertically at a velocity of 4m/s. How fast will the shadow of the balloon move alone the roof if it traveled 25 m vertically.

Image link:http://bit.ly/rem8PG


Homework Equations





The Attempt at a Solution



I don't know how to start this. I don't understand the nature of the shadow and why did it bounce off the wall like as shown in the image.

What relationship should i use? Please help me to solve this step by step. I'm willing to learn.
 
Last edited by a moderator:
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Myung said:

Homework Statement



A hemispherical dome has a diameter of 100m. A search light was placed at point A as shown at the middle of the dome at B. A balloon was released vertically at a velocity of 4m/s. How fast will the shadow of the balloon move alone the roof if it traveled 25 m vertically.

Image link:http://bit.ly/rem8PG


Homework Equations





The Attempt at a Solution



I don't know how to start this. I don't understand the nature of the shadow and why did it bounce off the wall like as shown in the image.

What relationship should i use? Please help me to solve this step by step. I'm willing to learn.
The shadow isn't bouncing off the inside of the dome. That line is just a radius of the dome, from the light out to the hemispherical wall.
 
Last edited by a moderator:
Mark44 said:
The shadow isn't bouncing off the inside of the dome. That line is just a radius of the dome, from the light out to the hemispherical wall.


Oh, so using that the value of the shadow will have height of 25 m which is 50m from point B after the instant of traveling upwards. But what is the use of the velocity of the balloon? What variables can I use to get the speed of the shadow?
 
The shadow travels along the curved surface of the dome. As the balloon rised 25 m. the shadow will move along an arc whose length is r * [itex]\theta][/itex].
 
Mark44 said:
The shadow travels along the curved surface of the dome. As the balloon rised 25 m. the shadow will move along an arc whose length is r * [itex]\theta][/itex].

I can't get θ without knowing how long did the balloon fly over B. If I only how long it took then I would have a fixed value after it traveled solving an angle at point A and getting θ by sine-law and supplementary angles.
 
This is what I have so far:

Since we are looking for velocity of shadow
let that be = d(h)/d(t)

and height of shadow = h

So Sinθ = h/50m
derivative of this equation is:
Cosθ(dθ/dt) = [50m(1)[d(h)/d(t)] - h(0)] / 2500



I have no values for θ and (dθ/dt) if I can get this I can get the d(h)/d(t) which is the main requirement of this equation. Still I haven't used the 4m/s velocity of the balloon from point B, I know that has a significant role in solving this but I can't seem to use it. I tried to get it's height after the instant but there is no time given. Help guys?
 
Mark44 said:
The shadow travels along the curved surface of the dome. As the balloon rised 25 m. the shadow will move along an arc whose length is r * [itex]\theta][/itex].

Thank you this helped me solve the equation. The speed of the shadow is 6.4m/s
 

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