How Fast Must a High Jumper Launch to Clear 2.10m?

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To clear a height of 2.10m, a high jumper must launch with a minimum speed of 6.47m/s. The jumper crosses the bar at a speed of 0.8m/s, which is the vertical component of the jump. The discussion highlights the importance of understanding that mass does not affect the falling speed due to gravity. The jumper's launch angle and time of flight were noted as missing variables that could aid in solving the problem. Overall, the calculation emphasizes the principles of projectile motion and free fall.
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With what minimum speed must a high jumper leave the ground to raise his center of mass by 2.10m and cross the bar with a speed of 0.8m/s?

For this question, I'm not sure how to proceed, and if its surely the correct way to do so but here's what I've done.

Since the jumper is crossing the bar at 0.8m/s, I know that the vertical vector is 0.8m/s. But the diagonal vector, similar to one in a horizontally launched projectile, I am having trouble determining. I feel there is not enough information for me to answer this question. If I knew the distance travelled, or time in the air, or even an angle of launch it might be able to lead me somewhere. Anyone see a solution with only those values given?

thx
 
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Nevermind, I found the answer, mass is negliable because it doesn't affect the falling speed of the object. All things fall at the same rate due to the constant gravity. Just like, if you have a frictionless ramp, there is nothing opposing the object from rolling down it, hence its similar to an object in free fall.

I got my ans outt o 6.47m/s if you guys want to do it yourselves.
 
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