How fast would a body reach thermal equilibrium ?

AI Thread Summary
The discussion centers on how quickly a 1 kg steel cube would reach thermal equilibrium at room temperature (20°C) in an ideally infinite room. Factors influencing the heating rate include the cube's surface area and the movement of air, which can enhance energy exchange. Newton's law of cooling is suggested as a method to calculate the heat transfer, represented by the equation dQ/dt = hA(T_room - T_cube), where A is the surface area and h is the heat transfer coefficient. The conversation acknowledges that the equilibrium temperature would be slightly lower than 20°C. Understanding these principles is essential for accurately estimating the time to reach thermal equilibrium.
Edi
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For example, I place a simple steel cube weighting 1 kg in a room [filled with air] at 20C [room temperature]. - how fast would the cube heat up to 20C (yes, actually equilibrium would be a bit lower than 20C, but lets.. imagine that is is a infinitely large room and .. yes, you get it ) ?
Yes, I know that increasing surface area would increase the rate of energy exchange and moving air [wind] would speed up the process too.. but I don't know the exact figures and formulas.. :(
 
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Edi said:
For example, I place a simple steel cube weighting 1 kg in a room [filled with air] at 20C [room temperature]. - how fast would the cube heat up to 20C (yes, actually equilibrium would be a bit lower than 20C, but lets.. imagine that is is a infinitely large room and .. yes, you get it ) ?
Yes, I know that increasing surface area would increase the rate of energy exchange and moving air [wind] would speed up the process too.. but I don't know the exact figures and formulas.. :(
I'd use Newton's law of cooling.
\frac{dQ}{dt}=hA(T_{\text {room}}-T_{\text {cube} }) where A is the surface area of the cube and h is the heat transfer coefficient (depending on the material of the cube).
 
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