How High Can Electrical Potential Get Near Large Charges?

AI Thread Summary
The discussion focuses on calculating the electric potential at a point 3 meters away from two charges, 3μC and 6μC. The initial calculations mistakenly presented potential energy instead of electric potential, leading to confusion over the high values obtained. It is clarified that the correct unit for electric potential is volts, not joules. The charges used are significant enough to produce high voltages at the given distance, which is expected. The conversation emphasizes the importance of distinguishing between potential and potential energy in electrostatics.
Latsabb
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The problem is to find the potential at a point that is 3 meters away from two charges. (one 3 meters above, and the other 3 meters below)

q1=3μC
q2=6μC

I put that Ep=Epq1+Epq2

Epq1=K*q1/r1
Epq2=K*q2/r2

K=1/(4πε0)=8.988x109

This gives me:

Epq1=8.988x109*(3x10-6/3)=8988J

Which immediately set some bells off for me. Isnt that quite a bit of energy for a charge three meters away? By the same formula, Epq2 equals 17976J, for a total potential of 26964J. Maybe I am wrong, but it seems like a very high potential. I will admit that I haven't wrapped my head around how large of charge a Coulomb is, so maybe 3μC and 6μC are very large amounts of charge, but something seems wrong to me...

Can someone take a look, and see if I did something wrong? Thank you.
 
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Hello, Latsabb.

Note that you are calculating potential, not potential energy. The unit of potential is not J.

A μC is a large amount of charge for a particle. So, a large value of potential in this problem is to be expected.
 
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Ok, thank you. Being that I am not calculating potential energy, that would make this... Volts? So I should be replacing my Ep's with V?
 
Yes. So, you are getting some "high" voltages because your charges are on the order of a few μC and your distances are on the order of a few meters.
 
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