Suppose a 180 kg motorcycle is heading toward a hill at a speed of 29 m/s. The two wheels weigh 12 kg each and are each annular rings with an inner radius of 0.280 m and an outer radius of 0.330 m.
How high can it coast up the hill, if you neglect friction in m?
*m = 180 kg
*v = 29 m/s
*h = 32 m
2. Homework Equations
mgh = 1/2 m v^2 + 1/2 I w^2
The Attempt at a Solution
First thing I did is finding the moment of inertia for the wheels, which is 1/2 m (b^2 + a^2) then I multiplied it by 2 since there are two wheels.
I then plugged that number for "I" in the above equation. I found w by dividing the given velocity by the outer radius(not sure if that is right) and then I had all the variables and solved for h but got an unreasonable number! bigger that the actual height of the hill.