How High Should I Drop My Weapon Sights for a 2.2 M/S Recoil Simulation?

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To simulate rifle recoil for weapon sights, the required drop height can be calculated using the conservation of energy principle. Given the weights of the sights at 2.2 lbs and 2.6 lbs, and the target impact speed of 2.2 meters per second, the formula mgh = 1/2 mv² can be applied. This simplifies to h = v² / (2g), where g is the acceleration due to gravity (9.81 m/s²). The calculated height will determine how far each sight needs to be dropped to achieve the desired speed upon impact. This method effectively models the recoil effect in a controlled environment.
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I need to do a rifle recoil simulation to some weapon sights. I have two of them. One weighs 2.2 lbs and the other 2.6 lbs. I need them to be going 2.2 meters a second when the hit the ground.

How high do I have to drop each one?
 
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Seems like a strange thing to do to a rifle.

Objects accelerate downward at g (9.81 m/s2), which is the acceleration of gravity at sea level. If an object starts are rest and falls, then one can use conservation of energy - gravitational energy (mgh) becomes kinetic energy (1/2 mv2), or

mgh = 1/2 mv2, which can be simplified to find h as a function of v.
 
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